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2 years ago

Find the degree of the monomial.3b2c

Mathematics

1 answer:

garik1379 [7]2 years ago

8 0

Answer:

Step-by-step explanation:

The degree of the given monomial = 2 + 1 = 3

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Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

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2 years ago

What value of y makes the equation true. y+2.9=11

yawa3891 [41]

Answer:

y = 8.1

Step-by-step explanation:

y+2.9=11

Subtract 2.9 from each side

y+2.9-2.9 = 11-2.9

y =8.1

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2 years ago

Let f(x) = 2x^2 - 4x + 1 <br><br> Find the values of f(1), f(0), f(2), f(-2), f(a)

Nataly [62]

Answers:

f(1) = -1

f(0) = 1

f(2) = 1

f(-2) = 17

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2 years ago

The highest point in North Carolina is Mt. Mitchell, with a height of 6,684 feet. Write the height of Mt. Mitchell as an integer

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1 year ago

Parameter and Statistic. In a Harris Interactive survey of 2276 adults in the United States, it was found that 33% of those surv

ankoles [38]

Answer:

Our population of interest represent all the adults in United states who never travel using commercial airlines.

The sample on this case represent the people surveyed in United States who never travel using commercial airlines.

For this case the value obtained $\hat p =0.33$ represent a statistic since is a value who represent the sample not the population. Our population parameter is not known and is given by $p$

Step-by-step explanation:

A statistic is a "characteristic of a sample". And the statistic allows "estimate the value of a population parameter".

A parameter is a value who represent the population of interest.

For this case we have a sample size of size n = 2276

The proportion estimated $\hat p$ of people that nevel travel using commercial airlines was:

$\hat p = \frac{x}{2276}=0.33$ or 33%

Our population of interest represent all the adults in United states who never travel using commercial airlines.

The sample on this case represent the people surveyed in United States who never travel using commercial airlines.

For this case the value obtained $\hat p =0.33$ represent a statistic since is a value who represent the sample not the population. Our population parameter is not known and is given by $p$

4 0

2 years ago

Find the degree of the monomial.3b2c​

Find the degree of the monomial.3b2c