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2 years ago

8

Help ASAP!!!!!!!!!!!!!!!!!???????????

1 answer:

sattari [20]2 years ago

7 0

Answer:

it would be number A. number 1

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the length of a rectangle is five feet less than its width. If the area of the rectangle is 84 square feet, find its dimensions

KIM [24]

Let
x---------> the length of the rectangle
y--------> the width of the rectangle

we know that
A=84 ft²
[area of rectangle]=x*y-----> 84=x*y-----> equation 1
x=y-5------> equation 2
substitute 2 in 1
84=[y-5]*y-----> 84=y²-5y---------> y²-5y-84=0

using a graph tool-----> to resolve the second order equation
see the attached figure

the solution is
y=12
x=y-5-----> x=12-5-----> x=7

the answer is
the length of the rectangle is 7 ft
the width of the rectangle is 12 ft

6 0

3 years ago

A. x = 2, y =6<br> B. x = 2, y =3<br> C. x =-2, y =3<br> D. x = -3, y =2

AlekseyPX

Answer:

The correct answer is A) x = 2 and y = 6

Step-by-step explanation:

In order to find the answer, we need to set the hypotenuses equal to each other. Then we can solve for y to get the equation.

y - 1 = x + 3

y = x + 4

Now we can do the same with the leg lengths.

y - 3 = 2x - 1

y = 2x + 2

Now that we have two equations, we can set them equal to each other to get the x value.

x + 4 = 2x + 2

4 = x + 2

2 = x

Now that we have x, we can plug it into any equation to get the y value.

y = x + 4

y = 2 + 4

y = 6

5 0

3 years ago

Read 2 more answers

What is p equal to? Also if you could, can you tell me how you do it so I can do the rest by myself.

svp [43]

Answer:

p=-54

Step-by-step explanation:

$- \frac{p}{6} = 9 \\ \frac{ - p}{6} = 9 \\ \frac{ - p}{6} \times 6 = 9 \times 6 \\ - p = 54 \\ p = - 54$

6 0

2 years ago

Read 2 more answers

2x+4-3x=-11 what is the answer

Pie

You want the xs and the numbers on different sides.
2x-3x=-11-4
-x=-15
divide x by a -1
x=15

8 0

2 years ago

Read 2 more answers

What is the dimension of a rectangle if the perimeter is 198

AfilCa [17]

Answer:

Length = 49.5 unit and width = 49.5 unit

Step-by-step explanation:

Given as , Perimeter of rectangle = 198 unit

so ,as Perimeter of rectangle = 2× ( Length + width)

Or, 198 = 2 × (Length + width)

Or, $\frac{198}{2}$ = length + width

So, length + width = 99 unit

Now to make area maximum

Length × width = maximum

Or, (99 - width ) × width = maximum

99 Width - width² = maximum Let width = W

Now differentiate both side with respect to W

D(99W - W²) $\frac{D(99w - w^2)}{Dw}$ = 0 as, constant diff is 0

So, 99 - 2w = 0

Or, w = $\frac{99}{2}$

Or, w = 49.5 unit and L = 99- 4905 = 49.5 unit Answer

3 0

3 years ago