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GaryK [48]
3 years ago
8

Elena’s dad buys another type of cell phone that also usually sells for $250. He pays 75% of the usual price. How much did he pa

y?
Mathematics
1 answer:
Mademuasel [1]3 years ago
8 0
Elena’s dad paid $187.5.
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For the given corporate bond, whose annual simple interest rate is provided, find the
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reagain and none that I know about the other day and none that I know that you are

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2 years ago
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Write 7 and 4/5ths as a decimal.
kipiarov [429]
It would be 7.8Since 7 and 4/5ths is a mixed fraction; you would multiply 7X5= 35, then add 35+4= 39. Then you get 39/5=7.8
4 0
3 years ago
(Based on Q1 ~ Q3) According to the Bureau of the Census, 18.1% of the U.S. population lives in the Northeast, 21.9% inn the Mid
vekshin1

Answer:

We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.

Step-by-step explanation:

The null Hypothesis: Geographical distribution of hotline callers could be the same as the U.S. population distribution

Alternative hypothesis: Geographical distribution of hotline callers could not be the same as the U.S. population distribution

The populations considered are the Midwest, South, Northeast, and west.

The number of categories, k = 4

Number of recent calls = 200

Let the number of estimated parameters that must be estimated, m = 0

The degree of freedom is given by the formula:

df = k - 1-m

df = 4 -1 - 0 = 3

Let the significance level be, α = 5% = 0.05

For  α = 0.05, and df = 3,

from the chi square distribution table, the critical value = 7.815

<u>Observed and expected frequencies of calls for each of the region:</u>

<u>Northeast</u>

Observed frequency = 39

It contains 18.1% of the US Population

The probability = 0.181

Expected frequency of call = 0.181 * 200 = 36.2

<u>Midwest</u>

Observed frequency = 55

It contains 21.9% of the US Population

The probability = 0.219

Expected frequency of call = 0.219 * 200 =43.8

<u>South</u>

Observed frequency = 60

It contains 36.7% of the US Population

The probability = 0.367

Expected frequency of call = 0.367 * 200 = 73.4

<u>West</u>

Observed frequency = 46

It contains 23.3% of the US Population

The probability = 0.233

Expected frequency of call = 0.233 * 200 = 46

x^{2} = \sum \frac{(O_{i} - E_{i})  ^{2} }{E_{i} } ,   i = 1, 2,.........k

Where O_{i} = observed frequency

E_{i} = Expected frequency

Calculate the test statistic value, x²

x^{2} = \frac{(39 - 36.2)^{2} }{36.2} + \frac{(55 - 43.8)^{2} }{43.8} + \frac{(60 - 73.4)^{2} }{73.4} + \frac{(46 - 46.6)^{2} }{46.6}

x^{2} = 5.535

Since the test statistic value, x²= 5.535 is less than the critical value = 7.815, the null hypothesis will not be rejected, i.e. it will be accepted. We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.  

7 0
3 years ago
Compared to others, which one of the following is not robust to outliers? a) Mean b) Median c) Mode d) 50th percentile
tatyana61 [14]

Answer:

The mean.

Step-by-step explanation:

The mean is not robust.

The presence of an outlier greatly affects the value of a mean.

An example will illustrate this.

Find the mean of  the numbers   2  3  5  6  34.

34 is an outlier. The mean = (2+3+5+6+34) / 5 = 10.

Now   if we replace the outlier with a number closer to the others:

Say we have 2 3 5 6 8 :

The mean = (2+3+5+6+8) / 5 =  4.8 which is a much truer measure of centrality than 10.

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Which ratios correctly compare bananas to apples, as shown in the picture ( 6 apples in a circle and 1 banana in the center ) ch
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Answer:

6:1

Step-by-step explanation:

There are 6 apples t o1 banana

(This is all i can do would have been easier with picture)

5 0
3 years ago
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