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Sergio039 [100]
3 years ago
12

Someone answer this please

Mathematics
1 answer:
Mice21 [21]3 years ago
5 0

Answer:

Which one?

Step-by-step explanation:

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−11 ≤ −5; Add 16 to both sides<br><br> The resulting inequality is:
Lemur [1.5K]

Answer:

True, (-∞, ∞)      5 ≤ 11

Step-by-step explanation:

−11 ≤ −5                       Add 16 to both sides

−11 + 16 ≤ −5 + 16

5 ≤ 11

3 0
2 years ago
Is 103 perfect square? show your work​
alexgriva [62]

Answer:

yes

Step-by-step explanation:

Could not simplify further

6 0
2 years ago
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What percentage of students earning degrees in 2009 were awarded a professional degree?
Dima020 [189]

data is not provided. what type of degrees? and which country?

5 0
3 years ago
The points (8, -10) and (-21, 4) form a line segment.
Citrus2011 [14]

Answer:

The coordinates of the midpoint are;

(-6.5, -3)

Step-by-step explanation:

Here, we want to get the midpoint of the line segment

To get this, we use the midpoint formula;

(x,y) = (x1 + x2)/2, (y1 + y2)/2

Thus;

(x,y) = (8 - 21)/2, (-10 + 4)/2

(x,y) = -13/2 , -6/2

(x,y) = (-6.5 , -3)

5 0
3 years ago
Through(-2,-3); parallel to 3x+2y=5
Vilka [71]

Step-by-step explanation:

Hey there!

<u>Firstly </u><u>find </u><u>slope </u><u>of</u><u> the</u><u> </u><u>given</u><u> equation</u><u>.</u>

Given eqaution is: 3x + 2y = 5.......(i)

Now;

slope(m1) =   \frac{ - coeff. \: of \: x}{coeff. \: of \: y}

or \: m1 =  \frac{ - 3}{2}

Therefore, slope (m1) = -3/2.

As per the condition of parallel lines,

Slope of the 1st eqaution (m1) = Slope of the 2nd eqaution (m2) = -3/2.

The point is; (-2,-3). From the above solution we know that the slope is (-3/2). So, the eqaution of a line which passes through the point (-2,-3) is;

(y-y1) = m2 (x-x1)

~ Keep all values.

(y + 3) =  \frac{ -  3}{2} (x + 2)

~ Simplify it.

2(y + 3)  = - 3x - 6

2y + 6 =  - 3x - 6

3x  + 2y + 12 = 0

Therefore, the eqaution of the line which passes through the point (-2,-3) and parallel to 3x + 2y= 5 is 3x + 2y +12 =0.

<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

8 0
2 years ago
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