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2 years ago

15

a circular pizza that is 10 inches in diameter is cut into 8 equal slices. what is the area of one of the slices? round to the n

earest tenth id needed

1 answer:

olga nikolaevna [1]2 years ago

3 0

The area of one slice is roughly 14.13

The area of the whole pizza is 113.1
Divide that by 8

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Given: -1/2x>6. Choose the solution set

Step2247 [10]

Answer:

B

Step-by-step explanation:

multiply both sides by 2 to eliminate the fraction

- x > 12

multiply both sides by - 1

Remembering to reverse the inequality symbol as a consequence

x < - 12 ← reverse symbol

⇒ { x | x ∈ R, x < - 12 } → B

5 0

2 years ago

Read 2 more answers

Find the equation of the line passing through points (-4,2) and (1,-6)

anzhelika [568]

Answer:

y + 6 = (-8/5)(x - 1) in point-slope form

Step-by-step explanation:

Moving from the 1st point to the first, we see that x (the 'run') increases by 5 from -4 to 1, and y (the 'rise') decreases by 8. Thus, the slope of the line through these two points is m = rise / run = -8/5

Now we have two points on the line, plus the slope. Let's write out the point-slope formula for the equation of a straight line:

y - k = m(x - h), where (h, k) is a point on the line and m is the slope of the line.

Here, using the point (1, -6), we obtain:

y + 6 = (-8/5)(x - 1) in point-slope form

8 0

2 years ago

I need more help with algebra please.

Triss [41]

Equation: 5x² - 3x - 14

= 5x² - 10x + 7x - 14

= 5x(x - 2) 7(x - 2)

= (5x + 7)(x - 2)

In short, Your Answer would be: Option B

Hope this helps!

6 0

2 years ago

Read 2 more answers

Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.

jek_recluse [69]

Answer:

Choice B: $y = 2\, (x - 6)^{2} + 5$ .

Step-by-step explanation:

For a parabola with vertex $(h,\, k)$ , the vertex form equation of that parabola in would be:

$\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}$ .

In this question, the vertex is $(6,\, 5)$ , such that $h = 6$ and $k = 5$ . There would exist a constant $a$ such that the equation of this parabola would be:

$y = a\, (x - 6)^{2} + 5$ .

The next step is to find the value of the constant $a$ .

Given that this parabola includes the point $(7,\, 7)$ , $x = 7$ and $y = 7$ would need to satisfy the equation of this parabola, $y = a\, (x - 6)^{2} + 5$ .

Substitute these two values into the equation for this parabola:

$7 = (7 - 6)^{2}\, a + 5$ .

Solve this equation for $a$ :

$7 = a + 5$ .

$a = 2$ .

Hence, the equation of this parabola would be:

$y = 2\, (x - 6)^{2} + 5$ .

4 0

3 years ago

Pleaseeeeeee help mee

BlackZzzverrR [31]

Answer:

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos( 3x - \frac{\pi }{3} ) = cos (\frac{\pi }{6} )$

$3x - \frac{\pi }{3} = \frac{\pi }{6}$

$3x - \frac{\pi }{3 } + \frac{\pi }{3} = \frac{\pi }{6} + \frac{\pi }{3}$

$3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}$

$x = \frac{\pi }{6}$

<u><em>Step(ii)</em></u>:-

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

<u><em>verification </em></u>:-

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

put $x = \frac{\pi }{6}$

$cos( 3(\frac{\pi }{6}) - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} = \frac{\sqrt{3} }{2}$

Both are equal

∴The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

4 0

2 years ago