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bonufazy [111]
3 years ago
9

Jake is the starting quarterback on his schools football team. He has completed 31 of his 73 passes this season.

Mathematics
1 answer:
lana [24]3 years ago
8 0

Answer:31/73*100

=42%

Step-by-step explanation:

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If h(a)= 3a+5 and h (a) = 27 the what is the value of a?
anzhelika [568]

Hey there!

Okay, so when you get a problem like this, all you need to do in insert the given value into the function and solve.

For example:

As you can see, they state that <em>(a) = 27, </em>so you insert 27 in for a in the function and it will look like this:

h(27) = 3(27) + 5

Now you solve on the right side of the equal sign:

3(27) = 81 (you multiply them)

81 + 5 = 86

When you plug the value of 27 in for a in this function, your output is equal to 86.

3 0
3 years ago
Read 2 more answers
What is -9 x (-3) ????
Natali5045456 [20]

Answer:

the answer is 27

Step-by-step explanation:

Since both intergers are negative, two negative intergers multiplied equal a positive answer. after wards just multiply 9 and 7 together. I hope this helped.

5 0
3 years ago
Find the distance between the two points (-10,3) and (0,27)​
crimeas [40]

Answer:

26 units

Step-by-step explanation:

\boxed{distance \: between \: 2 \: points =  \sqrt{ {(x1 - x2)}^{2} +  {(y1 - y2)}^{2}  } }

Using the formula above,

distance between (-10, 3) and (0, 27)

=  \sqrt{ {( - 10 - 0)}^{2}  +  {(3 - 27)}^{2} }

=  \sqrt{ {10}^{2}  + ( - 24) {}^{2} }

=  \sqrt{100 + 576}

=  \sqrt{676}

= 26 units

5 0
3 years ago
True or false variable is a letter used in place of a number
VikaD [51]
Answer: TRUE!


Variables ARE letters used in place of numbers absolutely
5 0
3 years ago
What are the potential solutions of In(x^2-25)=0?
Maslowich

Answer:

x =\pm \sqrt{26}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>

\implies log_e {(x^2-25)}= 0

<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>

  • If we have a logarithmic equation as ,

\implies log_a b = c

Then this can be written as ,

\implies a^c = b

In a similar way we can write the given equation as ,

\implies e^0 = x^2 - 25

  • Now also we know that a^0 = 1 Therefore , the equation becomes ,

\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}

<u>Hence</u><u> the</u><u> </u><u>Solution</u><u> </u><u>of </u><u>the</u><u> given</u><u> equation</u><u> is</u><u> </u><u>±</u><u>√</u><u>2</u><u>6</u><u>.</u>

6 0
3 years ago
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