we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form
or 
where
k is the constant of variation
in this problem we have
the point 
so

substitute


therefore
<u>the answer is</u>

Do you have the equation needed to solve for x?
I am going to guess you want to find a line which passes through the points (0,4) and (2,10)...
y₂-y₁ / x₂-x₁
10 - 4 / 2 - 0
6 / 2
3....slope
(0,4) .....b
y = 3x + 4
Answer:
1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64
2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21
Step-by-step explanation:
1. Maximize: P = 4x +4y
Subject to: 2x + y ≤ 20
x + 2y ≤ 16
x, y ≥ 0
Plot the constraints and the objective function Z, or P=4x+4y)
Push the objective function to the limit permitted by the feasible region to find the maximum.
Answer: Objective function is a maximum at (16,0),
Z = 4x+4y = 4(16) + 4(0) = 64
2. Maximize P = 3x + 2y
Subject to x + y ≤ 8
2x + y ≤ 13
x ≥ 0, y ≥ 0
Plot the constraints and the objective function Z, or P=3x+2y.
Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.
Answer: Objective function is at a maximum at (5,3),
Z = 3x+2y = 3(5)+2(3) = 21
It would be 63135 because that is the highest number you can multiply it into