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3 years ago

Which of the following is a characteristic of a line?

Mathematics

1 answer:

matrenka [14]3 years ago

4 0

Its length can be measured, it can be seen and, it is infinate in lenght

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People enjoyed attending the concert in the park. Twice as many men as women attended the concert. If the total attendance was 7

vazorg [7]

Hello! A way we could solve this equation is to divide 714 by three and then multiply the quotient by 2 to get the number of men that attended. 714/3 is 238. There were 238 women that attended the concert. 238 * 2 is 476. 476 + 238 = 714. There. There were 476 men that attended the concert.

5 0

4 years ago

Read 2 more answers

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

Please need help i need help i need help

xeze [42]

Set each expression from the parentheses equal to 0 separately like so:

Equation 1: x - 4 = 0

Equation 2: -5x + 1 = 0

Now for each equation solve for x!

Equation 1:

x +(- 4 + 4) = 0 + 4

x = 4

Equation 2:

-5x +( 1-1) = 0 - 1

-5x/ -5 = -1 / -5

x = 1/5

Check:

(4 - 4)(-5*4 + 1)

(0) (-20 + 1)

(0) (-19)

0 = 0 -------------------------> correct!

(1/5 - 4)(-5 * 1/5 + 1)

(-19/5)(-1 + 1)

(-19/5)(0)

0 = 0 -------------------------> correct!

smaller x = 1/5

larger x = 4

Hope this helped!

8 0

3 years ago

Read 2 more answers

E) Three friends were each given 25% of pie. What fraction of the pie was given altogether?

Leokris [45]

Answer:

3/4 or 75% or .75

Step-by-step explanation:

You would multiply 3 * .25 because there are three people getting 25% of a pie. All of the answers above are equivalent

4 0

3 years ago

Read 2 more answers

A triangle has sides of (2x), (x - 7) and (3x - 20).

LiRa [457]

2x+x-7+3x-20=87cm
6x-27=87
6x=114
x=19
Therefore the sides are:12cm, 38cm, and 37cm

7 0

3 years ago