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Slav-nsk [51]
3 years ago
14

The scale below represents which equation or inequality?

Mathematics
1 answer:
sp2606 [1]3 years ago
6 0
This is a
hope it helps
You might be interested in
Find the imaginary part of\[(\cos12^\circ+i\sin12^\circ+\cos48^\circ+i\sin48^\circ)^6.\]
iren [92.7K]

Answer:

The imaginary part is 0

Step-by-step explanation:

The number given is:

x=(\cos(12)+i\sin(12)+ \cos(48)+ i\sin(48))^6

First, we can expand this power using the binomial theorem:

(a+b)^k=\sum_{j=0}^{k}\binom{k}{j}a^{k-j}b^{j}

After that, we can apply De Moivre's theorem to expand each summand:(\cos(a)+i\sin(a))^k=\cos(ka)+i\sin(ka)

The final step is to find the common factor of i in the last expansion. Now:

x^6=((\cos(12)+i\sin(12))+(\cos(48)+ i\sin(48)))^6

=\binom{6}{0}(\cos(12)+i\sin(12))^6(\cos(48)+ i\sin(48))^0+\binom{6}{1}(\cos(12)+i\sin(12))^5(\cos(48)+ i\sin(48))^1+\binom{6}{2}(\cos(12)+i\sin(12))^4(\cos(48)+ i\sin(48))^2+\binom{6}{3}(\cos(12)+i\sin(12))^3(\cos(48)+ i\sin(48))^3+\binom{6}{4}(\cos(12)+i\sin(12))^2(\cos(48)+ i\sin(48))^4+\binom{6}{5}(\cos(12)+i\sin(12))^1(\cos(48)+ i\sin(48))^5+\binom{6}{6}(\cos(12)+i\sin(12))^0(\cos(48)+ i\sin(48))^6

=(\cos(72)+i\sin(72))+6(\cos(60)+i\sin(60))(\cos(48)+ i\sin(48))+15(\cos(48)+i\sin(48))(\cos(96)+ i\sin(96))+20(\cos(36)+i\sin(36))(\cos(144)+ i\sin(144))+15(\cos(24)+i\sin(24))(\cos(192)+ i\sin(192))+6(\cos(12)+i\sin(12))(\cos(240)+ i\sin(240))+(\cos(288)+ i\sin(288))

The last part is to multiply these factors and extract the imaginary part. This computation gives:

Re x^6=\cos 72+6cos 60\cos 48-6\sin 60\sin 48+15\cos 96\cos 48-15\sin 96\sin 48+20\cos 36\cos 144-20\sin 36\sin 144+15\cos 24\cos 192-15\sin 24\sin 192+6\cos 12\cos 240-6\sin 12\sin 240+\cos 288

Im x^6=\sin 72+6cos 60\sin 48+6\sin 60\cos 48+15\cos 96\sin 48+15\sin 96\cos 48+20\cos 36\sin 144+20\sin 36\cos 144+15\cos 24\sin 192+15\sin 24\cos 192+6\cos 12\sin 240+6\sin 12\cos 240+\sin 288

(It is not necessary to do a lengthy computation: the summands of the imaginary part are the products sin(a)cos(b) and cos(a)sin(b) as they involve exactly one i factor)

A calculator simplifies the imaginary part Im(x⁶) to 0

4 0
3 years ago
Simplify the given equation. 5x + 2(x - 3) = -2(x - 1)
svp [43]
On the left side, distribute the 2 to x and -3 so the left side should look like 5x+2x-6.

on the right, distribute the -2 to x and -1 so the right side should look like -2x+2.

combine like terms on the left to get 7x-6=-2x+2

add -2x from the right side to the left side to make the equation 9x-6=2 now it's a two step equation.
add 6 to 2 to get 9x=8. divide by 9 and x=8/9.


8 0
3 years ago
Round 4.75 to the nearest whole number
wolverine [178]
5. In 4.75 the 7 makes it round up to 5
8 0
3 years ago
Read 2 more answers
I NEED HELP in this
Alexeev081 [22]
As the image is magnified by a factor of 1: 7(1/4)
= 1: (29/4)
= 4/29.



The length of x must've been also increased by a factor of 4/ 29.

Using this,
The scaled value of x will be,

3(4/29)
= 12/29 units.
8 0
4 years ago
What does 74 divided by 8 equal
Darya [45]
8 goes into 74 nine times but there is a remainder of 2 

9 and a remainder of 2       or        9 and 1/4
8 0
3 years ago
Read 2 more answers
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