Well I got j for this. I picked a prim number for ex 5 and tries it with each problem.
Answer:
Rotation of a point through 180°, about the origin when a point is rotated about the origin through 180° in anticlockwise or clockwise direction, it takes the new position
Step-by-step explanation:
Answer:
I don't know how to do this thing
Acute scalene because they are all smaller than 90 degrees but different lengths
Lagrange multipliers:







(if

)

(if

)

(if

)
In the first octant, we assume

, so we can ignore the caveats above. Now,

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of

.
We also need to check the boundary of the region, i.e. the intersection of

with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force

, so the point we found is the only extremum.