We have three numbers to arrange so that 6 is 1/10 of the value of the other six.
Since position tells us whether we're talking about single, tens, hundreds, thousands (e.g. 25 is two times 10 plus five times 1) we know that the two sixes must be next to each other.
This leaves us with two options.
663 or 366.
In each of these cases the second 6 in the number is one tenth of the first 6.
If we look at the only other option: 636 we see that the second 6 is one hundredth of the value of the first 6.
Answer:
y = 15
Step-by-step explanation:
angle poq + angle qor equals mpor (120)
4y + 3y + 15= 120
7y+15=120
subtract 15 from both sides
7y=150
divide both sides by 7
y=15
check:
4(15) + 3(15) + 15 equals 120
60 + 45 + 15 = 120
120 = 120
use photo math For that Problem It would work Mate.
Answer:
because when the value of x is replaced in the factorisation it Will be equivalent to 100
