Please answer explain if so thank you

Vinil7 [7]

For the first one, the answer is -1 1/5

for the second one, the answer is 2.75

for the third one and fourth one,
To divide fractions take the reciprocal (invert the fraction) of the divisor and multiply the dividend. This is the quickest technique for dividing fractions. The top and bottom are being multiplied by the same number and, since that number is the reciprocal of the bottom part, the bottom becomes one

6 0

3 years ago

Kevin is making a picture frame. He has a piece of trim that is 5 feet long.

Mnenie [13.5K]

Answer:

4 and 4 inches left

Step-by-step explanation:

5 0

3 years ago

Whats the solution of <br> y = x +2 <br> 2x - 5y = 2

aleksandr82 [10.1K]

Answer:

x = -4, y = -2

Step-by-step explanation:

substitute for y

2x - 5(x + 2) = 2

distribute -5

2x -5x - 10 = 2

solve

-3x - 10 = 2

add 10 on both sides

-3x = 12

divide by -3

x = -4

now substitute for x in the equation y = x + 2

y = -4 + 2

y = -2

7 0

2 years ago

Bianca and Meredith are sisters. Meredith's height is 23 of Bianca's height plus 32 inches. Meredith is 60 inches tall. A girl i

jarptica [38.1K]

Answer:

Bianca's height = 42 inches

Step-by-step explanation:

Let x be the Bianca height.

Given:

Meredith height = 60 inches

We need to find the Bianca height.

Solution:

From the given statement the Meredith's height is $\frac{2}{3}$ of Bianca's height plus 32 inches, so the equation is.

Meredith's height = $\frac{2}{3}(Bianca\ height)+32$

Substitute Meredith's height in above equation.

$60=\frac{2}{3}x+32$

Now we solve the above equation for x.

$\frac{2}{3}x=60-32$

$\frac{2}{3}x=28$

By cross multiplication.

$x=\frac{3\times 28}{2}$

28 divided by 2.

$x= 3\times 14$

$x=42\ in$

Therefore, the height of the Bianca is 42 inches.

7 0

3 years ago

The test statistic of zequals2.32 is obtained when testing the claim that pgreater than0.3. a. Identify the hypothesis test as b

Sonja [21]

Answer:

a) We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:

Null hypothesis: $p \leq 0.3$

Alternative hypothesis: $p > 0.3$

Right tailed test

b) $p_v =P(z>2.32)=0.0102$

c) So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

Step-by-step explanation:

Part a: Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:

Null hypothesis: $p \leq 0.3$

Alternative hypothesis: $p > 0.3$

Right tailed test

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

For this case the statistic is given by $z_{calc}= 2.32$

Part b: Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.32)=0.0102$

Part c

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

6 0

3 years ago