Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
tte corresponding angle is angle 5
An equation that passes through the coordinates (3, -1) and has a slope of 2 would be y=2x-7 because since the slope is positive and is 2/1 the slope rises by 2 and runs 1 to right and eventually passes (3, -1) when it starts at -7 on the y-intercept. Answer: y=2x-7
Hope this helps you and would love brainliest!
Answer:
HEY BABE
Step-by-step explanation:
Answer: C
Step-by-step explanation:
On the left side, there are 2 triangles and 6 2's, so this equals 2x+12.
On the right side, there are 4 triangles and 2 2's, so this equals 4x+4.
Meaning 2x+12=4x+4.
12=2x+4
2x=8.