To isolate b on one side of the equation, all you have to do is subtract mx from both sides, so the answer is
y-mx =b
Define your variables:
Q: number of quarters
D: number of dimes
Next, create your equations
Q = 2D-4
25Q+10D=200
Because one variable (Q) is already written in terms of the other variable, D, you can already start solving with substitution.
25(2D-4)+10D=200
50D-100+10D=200
60D=300
D=5
Substitute D back into the other equation to find Q.
Q=2D-4
Q=2(5)-4
Q=6
Substitute D and Q into the second equation to check.
25Q+10D=200
25(6)+10(5)=200
150+50=200
This works, so the answer is right! Bill has 6 quarters and 5 dimes.
Answer:
Step-by-step explanation:
As with all word problems we first have to convert it to an equation or equations.
L = length of the Rectangle and W = its width
So L = 2 * W
A = area of the rectangle which is 128 cm^2
So A = L * W = 128 cm^2
substitute 2W for L from the 1st equation to give A = 2 * W * W = 2 * W^2 = 128 cm^2
Thus W^2 = 64 cm^2
finally W = 8 cm and therefore L = 2 * W = 16 cm
The perimeter P = 2 * (L+W) = 2* (8cm + 16cm) = 2 * 24cm = 48 cm
The value of b in the equation 5/2b+(-25/2) is 1.
