area of circle : πr²
area of sector : x/360 x πr²
firstly, you have to find. the area of a circle
π(6)² = 36π
then, find the area of the of the sector (not in the shape)
90°/360° x π(6)² = 12π
[90° is given)]
next, you just minus the total and the area of the sector.
36(3.14) - 12(3.14) = 75.36 units
All the trianges involved are isosceles right triangles. You know that the hypotenuse is the leg multplied by √2.
ML = KM = KL/√2 = 2/√2
ML = KM = √2
Hope that helps, have a good day :)
2/3*5/4
2*5/3*4
10/3*5
10/12 simplify
5/6
