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Bess [88]
3 years ago
11

Must a function that is decreasing over a given interval always be negative over that same interval? Explain.

Mathematics
1 answer:
kolbaska11 [484]3 years ago
5 0

Answer:

its called common sense

Step-by-step explanation:divide negative by the positive leaving you with the commomn answer thus its subtraction

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A number is k units to the left of 0 on the number line. describe the location of its opposite.
SSSSS [86.1K]
So it's on 0-k on the number line

If it's opposite that i.e. to the right if zero, then 0+k
7 0
3 years ago
The temperature is 8 degrees Celsius at midnight. By early morning, it had dropped 12 degrees Celsius. What was the temperature
erastovalidia [21]

Answer:

-4

Step-by-step explanation:

i could be wrong sooooooo

4 0
3 years ago
NEED HELP ASAP Which of the following equations describe the line shown below?
bagirrra123 [75]
(-1,6)(2,-6)
slope = (-6 - 6) / (2 - (-1) = -12/3 = -4

y = mx + b
slope(m) = -4
(-1,6)...x = -1 and y = 6
sub and find b, the y int
6 = -4(-1) + b
6 = 4 + b
6 - 4 = b
2 = b

so the equation is : y = -4x + 2 <=== here is one

y - y1 = m(x - x1)
slope(m) = -4
(-1,6)...x1 = -1 and y1 = 6
sub
y - 6 = -4(x - (-1) =
y - 6 = -4(x + 1) <=== here is one

y - y1 = m(x - x1)
slope(m) = -4
(2,- 6)...x1 = 2 and y1 = - 6
sub
y - (-6) = -4(x - 2) =
y + 6 = -4(x - 2) .... here is one, but it is not an answer choice
6 0
3 years ago
Sin 3pi divided by 4
KATRIN_1 [288]
Sin 3pi/4 is angle 135 degrees or 45 degrees below 180 degrees. Hence it's opposite side is 1 and adjacent is 1, implying the hypothenus is sqrt(2). Hence

Sin 3pi/4 = 1/sqrt(2). Now multiply by sqrt(2)/sqrt(2) to get:

[1/sqrt(2).] * [sqrt(2)/sqrt(2)] = sqrt2)/2
6 0
3 years ago
Solve this inequality 5 x + 2 &lt; 32
Hatshy [7]

Answer:

Here is your answer:

5x + 2 < 32

solution:

5x+ 2 < 32

or, 5x < 32-2

or, 5x < 30

or, 5x < 30/2

or, 5x < 15

or, x < 15/3

or, x < 5

therefore, x < 5 <u>ans</u>

<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>you</u></em>

7 0
3 years ago
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