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OverLord2011 [107]
3 years ago
10

Which equation is perpendicular to y = 4x - 6 and passes through point (8, 12).

Mathematics
1 answer:
sergeinik [125]3 years ago
7 0

Answer:

The line is ;

4y = -x + 56

or

y = -x/4 + 14

Step-by-step explanation:

Generally, the equation of a straight line is;

y = mx + c

where m represents the slope

so for y = 4x - 6

The slope is 4

If two lines are perpendicular, the product of their slopes is -1

So for the second line, the slope will be -1/4

The equation in the point slope format will be ;

y-12 = -1/4(x-8)

y-12 = -x/4 + 2

Multiply through by 4

4y-48 = -x + 8

4y = -x + 8 + 48

4y = - x + 56

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\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ -5X-2Y+Z=9 \end{gathered}

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\begin{gathered} -2\cdot(\frac{-9-2Y+Z}{5})+Y-2Z=-8 \\ 7\cdot(\frac{-9-2Y+Z}{5})+Y+Z=-1 \end{gathered}

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