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kolezko [41]
2 years ago
8

How much is the percent change if the price was $75 and now it is $300?

Mathematics
1 answer:
ale4655 [162]2 years ago
6 0

Answer:

300 percent change

Step-by-step explanation:

300 is 400 percent of 75.(75x4 is 300.) Therefore, the percent change is

400 - 100 = 300.

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The South Coast Air Basin (Los Angeles, Orange, and San Bernardino counties) does not meet the air quality standards for carbon
Archy [21]

Answer:

0.2225 gr/mile

Step-by-step explanation:

Let's work out first the amount of CO sent out in 1990.

The population we estimated in 12.5 million people with a total of driven miles per year of about  

12.5 million*8,700 = 108,750 million miles.

With an CO emission factor of 0.9 g per mile, we would have a total of CO emitted rounding 0.9*180,750 = 97,875 million grams

Now, we must estimate the population for 2020.

Since we are assuming an exponential growth, the population in year t is given by a function

\bf P(t)= Ce^{kt}

where C and k are constants to be determined.

We can take 1980 as year 0. This way calculations are lighter. 1990 is year 10 and 2020 is year 20.

So P(0) = 10.3 and C=10.3

So far we have

\bf P(t)= 10.3e^{kt}

Given that P(10)=12.5

\bf 10.3e^{k*10}=12.5\rightarrow e^{10k}=\frac{12.5}{10.3}=1.21359\rightarrow \\10k=log(1.21359)\rightarrow k=0.01936

And the function that models the population growth is

\bf P(t)= 10.3e^{0.01936t}

We need P(20)

\bf P(20)= 10.3e^{0.01936*20}=10.3e^{0.38717}=15.17\;million

If the miles driven per person per year remains constant at 8700 mi/yr.person, then we have a total miles driven of

15.17*8,700=131,979 million miles, so the CO emitted would be 0.9*131,979=118,781.1 million grams.

The 30% of the CO sent out in 1990 is 0.3*97,875=29,362.5 million grams.

We must reduce 118,781.1 down to 29,362.5

Hence the new CO emission factor would be

29,362.5/131,979 = 0.2225 gr/mile

6 0
3 years ago
A pie shop charges $4 for a slice of pie. They cut each whole pie into 6 slices. How much money will the pie shop make if they s
Likurg_2 [28]
$120

4x6=24
24x5=120
YW
8 0
3 years ago
How many times greater is the value of 4 in 547 than the value of the 4 and 84​
sesenic [268]

Answer:

10

Step-by-step explanation:

How many times greater is the value of 4 in 547 than the value of the 4 and 84​?

547: 500 + 40 + 7

5 is in the hundreds place

4 is in the tens place

7 is in the ones place

84: 80 + 4

8 is in the tens place

4 is in the ones place

The value of 4 in 547 is 10 times greater than the value of 4 in 84.

Since the 4 in 547 is in the tens place, while the 4 in 84 is in the ones place.

Also, 4 * 10 = 40

Hope this helps!

6 0
2 years ago
Solve the formula for h: A=1/2bh+3
olga55 [171]

cross multiply the equation to give you

1= a(2bh+3)

divide both sides by a(2b+3)

answer is 1/2ab+3 = h


5 0
3 years ago
Read 2 more answers
You are given 1000 one dollar bills and 10 envelopes. Put the bills into the envelopes in such a way that someone can ask you fo
taurus [48]

Answer:

We can do it with envelopes with amounts $1,$2,$4,$8,$16,$32,$64,$128,$256 and $489

Step-by-step explanation:

  • Observe that, in binary system, 1023=1111111111. That is, with 10 digits we can express up to number 1023.

This give us the idea to put in each envelope an amount of money equal to the positional value of each digit in the representation of 1023. That is, we will put the bills in envelopes with amounts of money equal to $1,$2,$4,$8,$16,$32,$64,$128,$256 and $512.

However, a little modification must be done, since we do not have $1023, only $1,000. To solve this, the last envelope should have $489 instead of 512.

Observe that:

  1. 1+2+4+8+16+32+64+128+256+489=1000
  2. Since each one of the first 9 envelopes represents a position in a binary system, we can represent every natural number from zero up to 511.
  3. If we want to give an amount "x" which is greater than $511, we can use our $489 envelope. Then we would just need to combine the other 9 to obtain x-489 dollars. Since x-489\leq511, by 2) we know that this would be possible.

4 0
3 years ago
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