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2 years ago

Round 0.8\0.6 to the nearest hundredth

Mathematics

1 answer:

madam [21]2 years ago

3 0

Answer:

0.8/0.6=1.33333 and to the nearest hundredth is 1.33

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Which of the following best describes the technique used to graph the equation y = 5x + 10using the slope and y-intercept?

nikdorinn [45]

The last one. Mark a point at 10 on the y-axis, go up 5 and right one and mark this point.

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2 years ago

A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop

Helen [10]

Answer:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

3 0

3 years ago

What is the gradient of the graph shown?

sladkih [1.3K]

Answer:

gradient = $\frac{1}{3}$

Step-by-step explanation:

calculate the gradient m using the gradient formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 6, 0) and (x₂, y₂ ) = (0, 2) ← 2 points on the line

m = $\frac{2-0}{0-(-6)}$ = $\frac{2}{0+6}$ = $\frac{2}{6}$ = $\frac{1}{3}$

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1 year ago

Solve this equation q - 17 = 18<br><br> Thanks!

Lisa [10]

Answer:

q =1

Step-by-step explanation:

q=17-18

.•. q=1

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X-2>5 <br> I need a person that can give me answers<br> Skpe at Kazuto Kirigaya king jolt 07

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