This is simple to solve as all we need to do is setup a basic equation. An equation that could represent this is

where x is equal to the amount of wire left on the reel.



Using this information, we can see that
there are 1,873 feet of wire left on the reel.
Answer:
7.96
Step-by-step explanation:
Answer:
![\displaystyle \boxed{8[x + 2][x^2 - 2x + 4]}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cboxed%7B8%5Bx%20%2B%202%5D%5Bx%5E2%20-%202x%20%2B%204%5D%7D)
Step-by-step explanation:
Use the Difference of Cubes [(a³ - b³)(a² + 2ab + b²)] to figure this out:
![\displaystyle 8x^3 + 64 \\ 8[x^3 + 8] \\ \\ x + 2 = \sqrt[3]{x^3 + 8}](https://tex.z-dn.net/?f=%5Cdisplaystyle%208x%5E3%20%2B%2064%20%5C%5C%208%5Bx%5E3%20%2B%208%5D%20%5C%5C%20%5C%5C%20x%20%2B%202%20%3D%20%5Csqrt%5B3%5D%7Bx%5E3%20%2B%208%7D)
Then, since the divisor\factor is in the form of <em>x - c</em>, use what is called Synthetic Division. Remember, in this formula, −c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
−2| 1 0 0 8
↓ −2 4 −8
___________
1 −2 4 0 → 
You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [x³ + 8]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x², the −2x follows right behind it, then 4, giving you the other factor of
, attaching this to the first two factors you started out your work on:
![\displaystyle \boxed{8[x + 2][x^2 - 2x + 4]}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cboxed%7B8%5Bx%20%2B%202%5D%5Bx%5E2%20-%202x%20%2B%204%5D%7D)
I am joyous to assist you anytime.
Answer:
see explanation
Step-by-step explanation:
In 13 - 17
Consider the factors of the constant term which sum to give the coefficient of the x- term
13
x² - x - 42 = (x - 7)(x + 6)
15
x² + x - 6 = (x + 3)(x - 2)
17
x² - 27x + 50 = (x - 25)(x - 2)
19
r² - 25 ← is a difference of squares and factors in general as
a² - b² = (a - b)(a + b) , thus
r² - 25
= r² - 5² = (r - 5)(r + 5)