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2 years ago

Although you can draw an infinite number of lines through the midpoint of a

Mathematics

1 answer:

rosijanka [135]2 years ago

6 0

Answer: Perpendicular

Step-by-step explanation: Took the quiz :)

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If mercy chews an average of 32 sticks of gum per month, how many months will it takes her to chew 2,400 sticks of gum?

vlabodo [156]

Answer:

75 months

Step-by-step explanation:

2400/32=

5 0

3 years ago

Read 2 more answers

Kelli is searching for a new daycare center for her child. At Lori's Local Daycare, there is a ratio of 2 caretakers for every 7

solong [7]

Answer:

243 people

Step-by-step explanation:

Kelli is searching for a new daycare center for her child. At Lori's Local Daycare, there is a ratio of 2 caretakers for every 7 children. If there are 189 total children, then how many people are at the daycare facility?

The ratio is given as:

Caretakers : Children

2 : 7

= In fraction = 2/7

If there are 189 total children, then how many people are at the daycare facility?

Step 1

We calculate the number of caretakers is there are 189 children

7 children = 2 caretakeras

189 children = x

Cross Multiply

7x = 189 × 2

x = 189 × 2/7

x = 54 caretakers

Step 2

The total number of people at the daycare

= 189 children + 54 caretakers

= 243 people

5 0

2 years ago

X<7, x=6<br> True or false<br><br> Help please

slamgirl [31]

Answer:

true

Step-by-step explanation:

if we say x is less than 7 and x is equal to 6 it makes sense that 6 is less than 7

4 0

2 years ago

Read 2 more answers

The velocity of an automobile starting from rest is given by the equation below, where v is measured in feet per second and t is

maria [59]

Answer:

a. At t = 5 s

$a(5)=\frac{1785}{\left(6(5)+17\right)^2}=\frac{1785}{2209}\approx0.808 \frac{ft}{s^2}$

b. At t = 10 s

$a(10)=\frac{1785}{\left(6(10)+17\right)^2}=\frac{255}{847}\approx0.301 \frac{ft}{s^2}$

c. At t = 20 s

$a(20)=\frac{1785}{\left(6(20)+17\right)^2}=\frac{1785}{18769}\approx0.095 \frac{ft}{s^2}$

Step-by-step explanation:

We know that the velocity function is given by

$v(t)=\frac{105t}{6t+17}$

Acceleration is the rate of change of velocity so we take the derivative of the velocity function with respect to time.

$a(t)=\frac{dv}{dt}=\frac{d}{dt} (\frac{105t}{6t+17})$

$\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\105\frac{d}{dt}\left(\frac{t}{6t+17}\right)\\\\\mathrm{Apply\:the\:Quotient\:Rule}:\quad \frac{d}{{dx}}\left( {\frac{{f\left( x \right)}}{{g\left( x \right)}}} \right) = \frac{{\frac{d}{{dx}}f\left( x \right)g\left( x \right) - f\left( x \right)\frac{d}{{dx}}g\left( x \right)}}{{g^2 \left( x \right)}}$

$105\cdot \frac{\frac{d}{dt}\left(t\right)\left(6t+17\right)-\frac{d}{dt}\left(6t+17\right)t}{\left(6t+17\right)^2}\\\\105\cdot \frac{1\cdot \left(6t+17\right)-6t}{\left(6t+17\right)^2}\\\\a(t)=\frac{1785}{\left(6t+17\right)^2}$