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3 years ago

How the heck do you do this

Mathematics

2 answers:

Stella [2.4K]3 years ago

6 0

The top one is 20 times as much but I really don't understand how to explain it.

Vladimir79 [104]3 years ago

4 0

If u know how exponents work, then you need to make the 10 into a 1000 and multiply it by 4.2. Then do the same process to the other # and divide the larger number by the smaller one. That it how you get the answer. Problem (1 or 2) is x times as much as the other problem.

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What is the slope of (3, 3) and (-6, -3)

Veronika [31]

Answer:

m=2/3

Step by Step Explanation:

x1,y1= 3,-6

x2,y2=3,-3

m={-3-3} (Fraction Form)

{-6-3}

Refine:

m={2}{3}

7 0

3 years ago

Read 2 more answers

A customer placed an order for muffins.The Baker has completed 37.5% of the order after baking 81 muffins. How many muffins did

IceJOKER [234]

81 divided by 37.5 equals 2.16, 2.16 would be equivalent to 1% so to find 100% we simbly multiply 2.16 by 100, 2.16 multiplied by 100 equates to 216, so the Baker is making 216 muffins.

If this is a word problem, put it into your own words in case of getting in trouble.

I hope this helped, have an awesome day!!

(brainliest is always appreciated)

6 0

3 years ago

Complete the table of values

Agata [3.3K]

Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, $3^{-2} =
\frac{1}{3^{2} }$ .
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, $(\frac{3}{4}) ^{3} = \frac{ 3^{3} }{4^{3} }$ .
3) The zero exponent rule says that any number raised to zero is 1. For example, $3^{0} = 1$ .


Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is $y = 4^{-x}$ . The x-values are:
1) x = 0
Plug this into $y = 4^{-x}$ to find letter a:
$y = 4^{-x}\\
y = 4^{-0}\\
y = 4^{0}\\
y = 1$

2) x = 2
Plug this into $y = 4^{-x}$ to find letter b:
$y = 4^{-x}\\ 
y = 4^{-2}\\ 
y = \frac{1}{4^{2}} \\ 
y= \frac{1}{16}$

3) x = 4
Plug this into $y = 4^{-x}$ to find letter c:
$y = 4^{-x}\\ 
y = 4^{-4}\\ 
y = \frac{1}{4^{4}} \\ 
y= \frac{1}{256}$


Problem 2
The x-values are in the left column. The title of the right column tells you that the function is $y = (\frac{2}{3})^x$ . The x-values are:
1) x = 0
Plug this into $y = (\frac{2}{3})^x$ to find letter d:
$y = (\frac{2}{3})^x\\
y = (\frac{2}{3})^0\\
y = 1$

2) x = 2
Plug this into $y = (\frac{2}{3})^x$ to find letter e:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\
y = \frac{4}{9}$

3) x = 4
Plug this into $y = (\frac{2}{3})^x$ to find letter f:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}$

-------

Answers:
a = 1
b = $\frac{1}{16}$ 
c = $\frac{1}{256}$
d = 1
e = $\frac{4}{9}$
f = $\frac{16}{81}$

5 0

3 years ago

Find the distance between the points (0,2)and (-5,-9)The answer must be a whole number or a fully simplified radical expression

LiRa [457]

Answer:

d = $\sqrt{146}$

Step-by-step explanation:

$d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d= \sqrt{(-5-0)^2+(-9-2)^2}\\d= \sqrt{(-5)^2+(-11)^2}\\d= \sqrt{25+121}\\d= \sqrt{146}$

7 0

3 years ago

If four times the sum of a number and 3 is divided by 2, the quotient is 0: find the number

AveGali [126]

The other number is -3.

Step-by-step explanation:

Step 1; First we develop formulae for the given information. A number is added with 3 and the resulting sum is multiplied by 4. This number is then divided by 2 and the quotient is 0. Assume the unknown number is x, then the given information is as follows

The quotient of $\frac{4(x+3)}{2}$ is 0. So $\frac{4(x+3)}{2}$ = 0.

Step 2; Now we solve the above equation. The denominator is taken to the RHS and the RHS remains zero.

$\frac{4(x+3)}{2}$ = 0, 4(x+3)= 0, 4x+ 12 = 0, 4x = -12, x = $\frac{-12}{4}$ = -3.

So the other number is -3.

3 0

3 years ago