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Olenka [21]
3 years ago
5

A plane takes off circles airport then lands at the same airport is this statement true or false

Mathematics
2 answers:
salantis [7]3 years ago
8 0
Yeaah It’s the first one (True )
Leya [2.2K]3 years ago
3 0

the statement is true.

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ASAP I NEED HELP PLEASE IM BEGGING YOU!!!!
Katyanochek1 [597]
All it is adding add both of the numbers that are on the top and then do the same
3 0
3 years ago
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Write a polynomial function of least degree with the given zero. -1+ √ 2, √ 3
kirill115 [55]

Answer:

f(x) = x^{4} + 2x³ - 4x² - 6x + 3

Step-by-step explanation:

Note that radical zeros occur in conjugate pairs, thus

- 1 + \sqrt{2} is a zero then - 1 - \sqrt{2} is also a zero

\sqrt{3} is a zero then - \sqrt{3} is also a zero

Thus the corresponding factors are

(x - (- 1 + \sqrt{2}) ), (x - (- 1 - \sqrt{2}) ), (x - \sqrt{3}), (x - (- \sqrt{3})), that is

(x + 1 - \sqrt{2}), (x + 1 + \sqrt{2}), (x - \sqrt{3}), (x + \sqrt{3})

The polynomial is then the product of the roots

f(x) = (x + 1 - \sqrt{2})(x + 1 + \sqrt{2})(x - \sqrt{3})(x + \sqrt{3})

     = ((x + 1)² - (\sqrt{2})²)((x² - (\sqrt{3})²)

     = (x² + 2x + 1 - 2)(x² - 3)

     = (x² + 2x - 1)(x² - 3) ← distribute

     = x^{4} - 3x² + 2x³ - 6x - x² + 3

     = x^{4} + 2x³ - 4x² - 6x + 3

6 0
3 years ago
Which congruence theorems can be used to prove △EFG ≅ △JHG? Check all that apply.
sasho [114]

Answer:

ASA  and AAS

Step-by-step explanation:

We do not know if these are right triangles; therefore we cannot use HL to prove congruence.

We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.

We are given that EF is parallel to HJ.  This makes EJ a transversal.  This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent.  We also know that ∠EGF and ∠HGJ are vertical angles and are congruent.  This gives us two angles and a non-included side, which is the AAS congruence theorem.

Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent.  Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.

4 0
3 years ago
Read 2 more answers
A homeowner wants to include a semicircular patio at the end of a square sandbox. She knows that the area of the semicircular pa
stepladder [879]

Answer:

8cm

Step-by-step explanation:

First you must know that the diameter of the semi-circular patio is equal to the length of one side of the square

Area of a semi circle = πr²/2

25.12  = πr²

25.12 = 3.14r²/2

r² = 25.12(2)/3.14

r² = 16

r = √16

r = 4

Get the diameter

d = 2r

d =2(4)

d = 8cm

Hence the length of the side of the square is 8cm

6 0
2 years ago
Which graph below shows a line that contains ordered pairs that are solutions of the equation shown?
Vinvika [58]

Given:

The equation is:

y=-x+4

To find:

The graph of the line that contains ordered pairs that are solutions of the given equation.

Solution:

We need to find the graph of the given equation.

We have,

y=-x+4

At x=0, we get

y=-0+4

y=4

So, the x-intercept of the given equation is at point (0,4).

At y=0, we get

0=-x+4

x=4

So, the y-intercept of the given equation is at point (4,0).

From the given graphs it is clear that the line in option C has x-intercept at point (0,4) and y-intercept at point (4,0).

Therefore, the correct option is C.

7 0
3 years ago
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