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3 years ago

The value of y varies directly with x. If x = 5 when y = 12, what is the value of x whon y = 30?

Mathematics

1 answer:

Brrunno [24]3 years ago

5 0

Step-by-step explanation:

y = kx, where k is a real constant.

When y = 12, x = 5.

=> (12) = (5)k, k = 2.4.

Therefore when y = 30,

x = y/k = (30)/(2.4) = 12.5.

The answer is 12.5.

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In the figure shown, ABCD is a parallelogram, AC = 16, and BD = 30 inches determine BC.

Flauer [41]

If it looks like this:

A -------------------- B
| |
| |
| |
C -------------------- D

Then BC is the hypotenuse of a right triangle with sides 16 and 30. Using the Pythagorean Theorem you can solve for the length of the hypotenuse:

$h^2 = 16^2 + 30^$
$h= \sqrt{256+900}$
$h =34$

7 0

3 years ago

What is the slope of the line that passes through (2, 12) and (4, 20)? (1 point)

serg [7]

M=20-12/4-2
m=8/2
m=4, is the answer

7 0

3 years ago

Suppose that prices of a certain model of a new home are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule t

levacccp [35]

Answer:

68% of buyers paid between $147,700 and $152,300.

Step-by-step explanation:

We are given that prices of a certain model of a new home are normally distributed with a mean of $150,000.

Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.

Let X = prices of a certain model of a new home

SO, X ~ Normal( $\mu=150,000 ,\sigma=2,300$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean price = $150,000

$\sigma$ = standard deviation = $2,300

Now, according to 68-95-99.7 rule;

Around 68% of the values in a normal distribution lies between $\mu-\sigma$ and $\mu-\sigma$ .

Around 95% of the values occur between $\mu-2\sigma$ and $\mu+2\sigma$ .

Around 99.7% of the values occur between $\mu-3\sigma$ and $\mu+3\sigma$ .

So, firstly we will find the z scores for both the values given;

Z = $\frac{X-\mu}{\sigma}$ = $\frac{147,700-150,000}{2,300}$ = -1

Z = $\frac{X-\mu}{\sigma}$ = $\frac{152,300-150,000}{2,300}$ = 1

This indicates that we are in the category of between $\mu-\sigma$ and $\mu-\sigma$ .

SO, this represents that percentage of buyers who paid between $147,700 and $152,300 is 68%.

7 0

4 years ago

Find the values of x and y 6 45° х y

Tanzania [10]

Answer:

Step-by-step explanation:

answer is c on edge

6 0

3 years ago

which number is the largest 1.2x10 to the forth power,4.5x10 to the negitive third power,3.8x10 to the third power,7.5x10 to the

Dennis_Churaev [7]

Answer:

2 × 10 to the fourth power. (160,000)

Step-by-step explanation:

We know that if it is a negative exponent that is also an odd number, it will not be the greatest/largest. 2 times 10 is 20 and then 20 to the fourth power is 160,000. 3.8 times 10 equals 38, then we put it to the third power and we will get 54,872. Finally, 7.5 times 10 equals 75 and when we put that to the third power, it becomes 421,875. Therefore, 2 times 10 to the fourth power is the greatest/largest.

4 0

3 years ago