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PilotLPTM [1.2K]
3 years ago
11

Which graph represents a function?

Mathematics
1 answer:
enyata [817]3 years ago
3 0

Answer:

D, the horizontal line is a function

Step-by-step explanation:

To pass the vertical line test, a vertical line cannot go through the function more than once

A is a vertical line so it will fail the vertical line test

B will fail the vertical line test at many points.  One example is at

x =0 where you can see it will intersect at two points

C will fail the vertical line test at many points.  One example is at

x =0 where you can see it will intersect at two points

D is a horizontal line.  This will pass the vertical line test

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Use the above graph to answer the following question. Which line indicates the demand curve? (1 point)
IRINA_888 [86]

Answer:

A - one

Step-by-step explanation:

A typical demand curve, in economics, depicts the relationship between price of a commodity on the y-axis, and quantity demanded on the x-axis.

The demand curve obeys the Law of Demand, which states that the higher the price, the lower the quantity demanded of that commodity, and vice versa, all things being equal. Thus, a typical demand curve will slope downwards, from left to the right.

Therefore, line 1 indicates the demand curve.

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3 years ago
A linear revenue function is R = 12x. (Assume R is measured in dollars.) what is the slope? What is the revenue received from se
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Answer:

12 ; 12 dollars

Step-by-step explanation:

Data provided in the question:

Revenue function, R = 12x

R is in dollars

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The slope can be found out by differentiating the above revenue function w.r.t 'x'

thus,

\frac{\textup{dR}}{\textup{dx}}= \frac{\textup{d(12x)}}{\textup{dx}}

or

slope = 12

Now, for the second case of selling one more unit i.e x = 1, the revenue can be obtained by substituting x = 1 in revenue function

therefore,

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2 years ago
What is the range of the data?
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is the difference between highest and lowest values.

Step-by-step explanation:

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The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
MAXImum [283]
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

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\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

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