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3 years ago

Which value could go in the blank cell so that the percentage of only children that

Mathematics

1 answer:

babunello [35]3 years ago

8 0

Answer:

maybe B

I am not to my answer

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SHOW WORK NEED ASAP

Semenov [28]

Answer:

rectangular tables

Step-by-step explanation:

x: how many tables

a) 49x/49=800/49

x=16.3

so roughly 16 tables

b) 64x/64=800/64

x= 12.5

so roughly 12(you round to nearest even number when it is .5)

c) Now we will calcuate how many people will fit using the number of fitting capacity

=16 (8)

128

=12(12)

=144

Therefore, the rect tables will fit more people

8 0

2 years ago

Both the La Plata river dolphin (Pontoporia blainvillei) and

Citrus2011 [14]

Answer:

1. A sperm whale is 3 orders of magnitude heavier than a La Plata river dolphin; 2. The radius of the larger ball is one (1) order of magnitude bigger than the radius of the smaller ball; 3. The volume of the larger ball is 3 orders of magnitude bigger than the volume of the smaller ball.

Step-by-step explanation:

If we expressed a number as:

$\\ N = a * 10^{b}$ (1)

Where

$\\ \frac{1}{\sqrt{10}} \leq a < \sqrt{10}$ (2)

$\\ 1 \leq a < 10$ (3)

Then, b represents the order of magnitude of such a number (Order of magnitude (2020), in Wikipedia).

The order of magnitude can be defined as "...the smallest power of ten needed to represent a quantity" (Weisstein, Eric W. "Order of Magnitude". From MathWorld--A Wolfram Web Resource).

Having gathered all this information, we can proceed as follows:

<h3>First case</h3>

The La Plata river dolphin weighs between 30 and 50kg and the sperm whale weighs between 35,000 and 40,000kg.

Then, considering (1) and (3) to express the dolphin and whale's weight (since in this way the order of magnitude is the same as the exponent part in the scientific notation):

$\\ 30kg \leq Dolphin_{weight} \leq 50kg$

$\\ 3*10^{1}kg \leq Dolphin_{weight} \leq 5*10^{1}kg$

$\\ 35000kg \leq Whale_{weight} \leq 40000kg$

$\\ 3.5*10^{4}kg \leq Whale_{weight} \leq 4.0*10^{4}kg$

Since the range for the weights are in the same order of magnitude for both dolphin and whale (considering the definition above):

$\\ Dolphin_{weight} = 10^{1}\;(order\;of\;magnitude=1)$

$\\ Whale_{weight} = 10^{4}\;(order\;of\;magnitude=4)$

Then

$\\ \frac{Whale_{weight} = 10^{4}}{Dolphin_{weight} = 10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = \frac{10^{4}}{10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{4-1}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{3}$

Thus

A sperm whale is 3 orders of magnitude heavier than a La Plata river dolphin.

<h3>Second case</h3>

Following the same reasoning, we can conclude that the radius of the larger ball is one (1) order of magnitude bigger than the radius of the smaller ball:

$\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = \frac{10^{1}}{10^{0}}$

$\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = 10^{1-0} = 10^{1}$

<h3>Third case</h3>

For this case, we need to calculate the volume of a sphere for both radii (1cm and 10cm).

The volume of a sphere is

$\\ V_{sphere} = \frac{4}{3}*\pi*R^{3}$

Then, the volume of the ball of radius 1cm is:

$\\ V_{radius=1} = \frac{4}{3}*\pi*(1cm)^{3}$

$\\ V_{radius=1} \approx 4.19*10^{0}cm^{3}$

And, the volume of the ball of radius 10cm is:

$\\ V_{radius=10} = \frac{4}{3}*\pi*(10cm)^{3}$

$\\ V_{radius=10} \approx 4.19*10^{3}cm^{3}$

Thus

$\\ \frac{10^{3}}{10^{0}} = 10^{3}$

As a result, the volume of the larger ball is 3 orders of magnitude bigger than the volume of the smaller ball.

4 0

3 years ago

Everything please helppppp!!

Soloha48 [4]

Answer:

Ok im, not 100% sure but the answer is for 1-10, 2-20, 3-40, 4-40

7 0

3 years ago

Read 2 more answers

You're playing a game when you defend your village from an orc invasion there are three characters elf hobbit or human and five

34kurt

The probability that you'll be a magic elf is $\frac{1}{15}$ or 6.66%.

Step-by-step explanation:

Step 1:

Let A be the event of you choosing an elf.

The probability of an event is given by dividing the number of favorable outcomes by the total number of outcomes.

Here the number of favorable outcomes is 1 and the total number of outcomes is 3 i.e. elf, hobbit or human.

The probability of choosing an elf, $P(A) = \frac{1}{3} .$

Step 2:

Let B be the event of you choosing magic as your defense.

In this situation, the number of favorable outcomes is 1 and the total number of outcomes is 5 i.e. magic, sword, shield, slingshot, or umbrella.

The probability of choosing magic as your defense, $P(B) = \frac{1}{5} .$

Step 3:

The probability of both events A and B happening, we multiply the individual probabilities.

$P(getting a magic elf) = (P(A))(P(B)) = (\frac{1}{3} )(\frac{1}{5} ) = \frac{1}{15} = 6.66\%.$

8 0

3 years ago

Given: F(x) = 2x - 1; G(x) = 3x + 2; H(x) = x 2 Find F[G(x)] - F(x). 4x + 4 4x + 2 4x

Allushta [10]

Answer:

4x + 4

Step-by-step explanation:

F(x) = 2x - 1

G(x) = 3x + 2

H(x) = x²

We have to calculate the expression F(G(x)) - F(x)

F(G(x)) means the composition of functions F(x) and G(x). In order to find F(G(x)) we have to replace ever occurrence of x in F(x) with the value of G(x). So,

F(G(x)) = 2(3x+2) - 1 = 6x + 4 - 1 = 6x + 3

Thus,

F(G(x)) - F(x) = 6x + 3 - (2x - 1)

= 6x + 3 -2x + 1

= 4x + 4

Therefore, the expression F(G(x)) - F(x) equals 4x + 4

4 0

3 years ago