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PilotLPTM [1.2K]
3 years ago
14

Answer this question please and thank you

Mathematics
2 answers:
WITCHER [35]3 years ago
4 0

39.273 ------> 39

- 8.58 ------> 9

----------------------

30.693 -----> 30

iragen [17]3 years ago
4 0
39.273-8.58=30.693
39-9=30
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Math question down below
SIZIF [17.4K]
To get the average, you must add all together and divide by the amount of numbers there are

(-4 - 6 - 3 - 1 + 0 + 2 - 1 - 3)/ 8

(-16)/8 = -2

-2 is your average

hope this helps
5 0
3 years ago
Read 2 more answers
What is the difference of the given values to the correct level of precision?
kari74 [83]

Answer: 16.31 L

22.108 L - 5.80 L = 16.308 L

The reason that the answer is only precise up to 2 decimals is because our least precise measurement goes as far as 2 decimals and you can only be as precise as your least precise measurement

8 0
3 years ago
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Pls help me simplify thisss
Step2247 [10]

9514 1404 393

Answer:

  2a(a^3 +a^3 b^2 +a b^2 +b^3)/(a^2 +b^2)

Step-by-step explanation:

Division is the same as multiplication by the inverse. Multiplication and division proceed left-to-right. So, we can rewrite the expression as ...

  \dfrac{a^3+a^3b^2+ab^2+b^3}{2a(a-b)^2}\times\dfrac{a^2-b^2}{a+2b}\times\dfrac{a^2+ab-2b^2}{a+b}\times\dfrac{4a^2}{a^2+b^2}\\\\=\dfrac{(a^3+a^3b^2+ab^2+b^3)(a-b)(a+b)(a+2b)(a-b)(4a^2)}{2a(a-b)^2(a+2b)(a+b)(a^2+b^2)}\\\\=\dfrac{4a^2}{2a}\cdot\dfrac{(a-b)^2}{(a-b)^2}\cdot\dfrac{a+2b}{a+2b}\cdot\dfrac{a^3+a^3b^2+ab^2+b^3}{a^2+b^2}\\\\=\boxed{\dfrac{2a(a^3+a^3b^2+ab^2+b^3)}{a^2+b^2}}

5 0
2 years ago
Round yo The nearest ten 834,692.<br> Help me please!!
Genrish500 [490]
The answer should be 834, 690

hope this helps!
8 0
3 years ago
Read 2 more answers
Help my sis needs help asap
Scorpion4ik [409]

Answer:

152 in^2

Step-by-step explanation:

If you take the left side and consider it a whole rectangle, you can calculate the area of that triangle to be 80. Using the same method, you can find the area of the rectangle of the right to be 72. Then add them together.

80 + 72 = 152 in^2

8 0
2 years ago
Read 2 more answers
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