To find the area of a triangle, you have to multiply the height and the base length, and divide that by two.
In this question, the height is 3 square units and the base length is 4 square units.
Therefore, to find the area, you must multiply 3 by 4, which is 12, and then divide this by 2, which is 6.
So the area of this triangle is 6 square units.
The measure of ∠ACB will be 110°
<u><em>Explanation</em></u>
According to the diagram below, and are the perpendicular bisectors of and respectively and they intersect side at points and respectively.
So, and
Now, <u>according to the postulate</u>, ΔAPE and ΔCPE are congruent each other. Also, ΔCFQ and ΔBFQ are congruent to each other.
That means, ∠PCE = ∠PAE and ∠FCQ = ∠FBQ
As ∠CPQ = 78° , so ∠PCE + ∠PAE = 78° or, ∠PCE = ° and as ∠CQP = 62° , so ∠FCQ + ∠FBQ = 62° or, ∠FCQ = °
Now, in triangle CPQ, ∠PCQ = 180°-(78° + 62°) = 180° - 140° = 40°
Thus, ∠ACB = ∠PCE + ∠PCQ + ∠FCQ = 39° + 40° + 31° = 110°
Surfae area
we have 5 faces for the top shape
6 faces for the bottom
find areas of both
top=3*3+3*3+3*3+3*3=45
bottom one=3*10+3*3+3*3+3*10+3*10+3*(10-3)=129
add
45+129=174 mm^2
answer is B
volue
top shape is 3*3*3=27 mm^3
bottom is 10*3*3=90
add
27+90=117 mm^3
answer is C
6. 174 m^2 B
7. 117 mm^2 C