Solve the system using substitution.
y + 8x = 10
2y - 4x = 40
(-1, [?])
2 answers:
Solve for
y
in the first equation.
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y
=
−
20
+
4
x
−
2
x
−
2
y
=
10
Replace all occurrences of
y
in
−
2
x
−
2
y
=
10
with
−
20
+
4
x
.
y
=
−
20
+
4
x
−
2
x
−
2
(
−
20
+
4
x
)
=
10
Simplify
−
2
x
−
2
(
−
20
+
4
x
)
.
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y
=
−
20
+
4
x
−
10
x
+
40
=
10
Solve for
x
in the second equation.
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y
=
−
20
+
4
x
x
=
3
Replace all occurrences of
x
in
y
=
−
20
+
4
x
with
3
.
y
=
−
20
+
4
(
3
)
x
=
3
Simplify
−
20
+
4
(
3
)
.
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y
=
−
8
x
=
3
The solution to the system of equations can be represented as a point.
(
3
,
−
8
)
The result can be shown in multiple forms.
Point Form:
(
3
,
−
8
)
Equation Form:
x
=
3
,
y
=
−
8
Y=10-8x. 2(10-8x)-4x=40, 20-16x-4x=40,x=-1. Y=10-8(-1)=10+8=18
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