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Anton [14]
3 years ago
12

Tom and Bob have a total of 49 toys if Bob has 5 more toys than Tom, how many toys does each one have

Mathematics
2 answers:
pickupchik [31]3 years ago
5 0
49 + 5 = 54

So the answer is 54
Andre45 [30]3 years ago
4 0
Let x and y are toys of tom and bob respectively
x+y=49
y=x+5----(bob hs 5 more toys than tom)
 substitute value of y
x+x+5=49
2x+5=49
2x=49-5
2x=44
x=22----tom has toy
y=27------bob has toy
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B) car B

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I hope I can help you have a great day :)

4 0
3 years ago
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89 (54x − 36) + 2 = −3/4 (−40 + 16x) + 90xsolve for x
Amiraneli [1.4K]
Hey! Just in case you have to show your work.

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7 0
2 years ago
John played a note on his tuba that vibrated the air 70 times per second. If he played the note for 5 seconds, how many times di
lutik1710 [3]
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3 years ago
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Need help please and thanks​
madreJ [45]

Answer:

2. n = 11

4. g = -2

6. t = 21

8. n = 4

10. y = -1

Step-by-step explanation:

2. 63  = -3(1 - 2n)

Dividing both the side by negative 3 we get

-21=1-2n\\2n=1+21\\2n=22\\n=\frac{22}{2} \\\therefore n=11

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First we will open the bracket by distributive property A( B +C) = AB + AC

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6.-3(t +5 ) + (4t + 2) = 8

Using distributive property A( B +C) = AB + AC we get

-3\times t + -3\times 5 + 4t + 2=8\\-3t-15+ 4t + 2=8\\t=8+15-2\\t=21\\\therefore t=21\\

8. -8 - n = -3(2n -4)

Using distributive property A( B +C) = AB + AC we get

-8 - n = -3\times 2n - -3\times4\\-8-n=-6n+12\\\textrm{all the n terms to the left inside and the constant of the right-hand side}\\6n-n=8+12\\5n=20\\n=\frac{20}{5}\\ \therefore n= 4

10. -4( 2 - y) + 3y = 3(y - 4)

Using distributive property A( B +C) = AB + AC we get

-4\times 2 --4\times y + 3y = 3\times y -3\times 4\\-8+4y+3y =3y-12\\\textrm{all the y terms to the left side and the constant to the right side}\\4y+3y-3y=-12+8\\4y=-4\\y=\frac{-4}{4}\\ \therefore y=-1

7 0
3 years ago
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