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inysia [295]
3 years ago
6

12,27,42,57

Mathematics
1 answer:
geniusboy [140]3 years ago
6 0
A1=12, a2=27, a3=42, etc. The pattern is that you’re always adding 15 after starting with 12. So the general rule is...

an=12+15(n-1)

So then...

a18=12+15(18-1)
a18=12+15(17)
a18=267
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What is the mean/average of the integers 2, 2, 2, 0, -2, -2
maks197457 [2]

Answer:

The answer is.

2+2+2+0-2-2/6.

2/6=1/3 or 0.333333333.

8 0
3 years ago
Lowe's 1/5 + 1/2 answer and said the answer was 2/7
Eva8 [605]
You got the sum right because 15+12=27
6 0
3 years ago
Read 2 more answers
Evaluate your expression for 20 miles walked.
professor190 [17]

Answer:

i am not sure but i thinks 2-1 is 1

Step-by-step explanation:

6 0
3 years ago
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You need to compute the a 90% confidence interval for the population mean. How large a sample should you draw to ensure that the
RSB [31]

Answer:

The sample size required is 102.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean <em>μ</em> is:

CI=\bar x\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

MOE= z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}

Given:

<em>σ</em> = 9.2

(1 - <em>α</em>)% = 90%

MOE = 1.5

The critical value of <em>z</em> for 90% confidence level is:

z_{0.10/2}=1.645

*Use a <em>z</em>-table.

Compute the value of <em>n</em> as follows:

MOE= z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}

      n=[\frac{z_{\alpha/2}\times \sigma}{MOE}]^{2}

         =[\frac{1.645\times 9.2}{1.5}]^{2}\\=101.795\\\approx102

Thus, the sample size required is 102.

5 0
3 years ago
The registration period for the race is under way, and as the word is getting out, the number of participants registering is gro
Olin [163]

y = a(1 + r)ˣ

a = 15  "<em>initial" means what you started with on the first day</em>

r = 6   <em>the rate it increased is the slope ((\frac{21 - 15}{2 - 1})</em>

y = 15(1 + 6)ˣ

Answer: y = 15(7)ˣ

3 0
3 years ago
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