Answer:
(a) 7.5 seconds
(b) The horizontal distance the package travel during its descent is 1737.8 ft
Step-by-step explanation:
(a) The given function for the height of the object is s = -16·t² + v₀·t + s₀
The initial height of the object s₀ = 900 feet
The initial vertical velocity of the object v₀
= 0 m/s
The time it takes the package to strike the ground is found as follows;
0 = -16·t² + 0×t + 900
900 = 16·t²
t² = 900/16 = 62.25
t = √62.25 = 7.5 seconds
(b) Given that the horizontal velocity of the package is given as 158 miles/hour, we have
158 miles/hour = 231.7126 ft/s
The horizontal distance the package covers in the 7.5 second of vertical flight = 231.7126 ft/s × 7.5 s = 1737.8445 feet = 1737.8 ft to one decimal place
The horizontal distance the package travel during its descent = 1737.8 ft.
Answer:
x=141
Step-by-step explanation:
(n-2)•180 = Sum of all the interior angles
n = # of sides
(7-2)•180
5•180
900= Sum of all the interior angles
Add all the angles and equal them to 900
125+122+131+x+7+x+107+x-15=900
Add all the numbers up first on the left side
477+3x=900
3x=423
x=141
Answer:
33.
Step-by-step explanation:
x^2 - 7x + 4.
The discriminant of the above
= b^2 - 4ac
= (-7)^2 - 4*1*4
= 49 - 16
= 33.
<span><span>9−5</span>>3</span><span><span>4></span>3
</span><span>True hope i helped</span>
Answer:x= 9
Step-by-step explanation:
-4(x+5) = 16
-4*x= -4x -4*5= -20
16 - -20= 36
-4x/-4= x 36/-4=9