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VARVARA [1.3K]
3 years ago
14

Solve the inequalities for x, and match each solution to its number line graph.

Mathematics
1 answer:
marysya [2.9K]3 years ago
8 0

Answer:

14

Step-by-step explanation:

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I need help how do you solve #4
Sloan [31]

A + B + C = 180

A = B --> B = A

A = 4·C --> C = 1/4*A

A + A + 1/4*A = 180

2.25*A = 180

A = 80

5 0
3 years ago
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6^2r=800 round it to the nearest hundreth
kogti [31]

Question: solve for r: 6 ^ (2r) = 800


Answer: 1.87


Step-by-step explanation:

6 ^ (2r) = 800

log(6 ^ (2r)) = log(800)

2r log(6) = log(800)

r = log(800) / (2 log(6))

r = 1.86537641979

round

r = 1.87

log can be any logarithm function.


6^(2×1.86) = 784.734328546

6^(2×1.87) = 813.365367336


7 0
3 years ago
The cost of one pound of bananas is greater than $0.41 and less than $0.50. Sarah pays $3.40 for x pounds of bananas. Which ineq
vredina [299]

Answer:

0.41<3.40/x<0.50

Step-by-step explanation:

Given that the cost of one pound of bananas is greater than $0.41 and less than $0.50. That is,

If the cost of one banana is P, then, the inequality will be

0.41 < P < 0.50

Sarah pays $3.40 for x pounds of bananas. The inequality that represents the range of possible pounds purchased will be achieved by below

3.40/0.41 = 8.29

3.40/0.50 = 6.8

Therefore, the inequality that represents the range of possible pounds purchased is

6 < x < 9 this is the same as 0.41<3.40/x<0.50

6 0
3 years ago
How can you use exponential growth or exponential decay to model the populations of endangered species?
hammer [34]

Answer:

help animals and clean up to help animals animals are friends not food

6 0
3 years ago
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A jewelry sells gold and platinum rings. Each ring is available in eight styles and is fitted with one of ten gemstone
katrin [286]

Answer: There are 160 different rings.

Step-by-step explanation:

The question is missing, i guess you want to know the number of different rings that the jewelry has:

For the material we have 2 options.

For the stile we have 8 options

For the gem we have 10 options.

Now, the total number of possible combinations is equal to the product of the number of options for each selection, this is:

Combinations = 2*8*10 = 160

4 0
3 years ago
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