4 because that is what's multiplied throughout
Answer:
a. closed under addition and multiplication
b. not closed under addition but closed under multiplication.
c. not closed under addition and multiplication
d. closed under addition and multiplication
e. not closed under addition but closed under multiplication
Step-by-step explanation:
a.
Let A be a set of all integers divisible by 5.
Let
∈A such that ![x=5m\,,\,y=5n](https://tex.z-dn.net/?f=x%3D5m%5C%2C%2C%5C%2Cy%3D5n)
Find ![x+y,xy](https://tex.z-dn.net/?f=x%2By%2Cxy)
![x+y=5m+5n=5(m+n)](https://tex.z-dn.net/?f=x%2By%3D5m%2B5n%3D5%28m%2Bn%29)
So,
is divisible by 5.
![xy=(5m)(5n)=25mn=5(5mn)](https://tex.z-dn.net/?f=xy%3D%285m%29%285n%29%3D25mn%3D5%285mn%29)
So,
is divisible by 5.
Therefore, A is closed under addition and multiplication.
b.
Let A = { 2n +1 | n ∈ Z}
Let
∈A such that
where m, n ∈ Z.
Find ![x+y,xy](https://tex.z-dn.net/?f=x%2By%2Cxy)
![x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)](https://tex.z-dn.net/?f=x%2By%3D2m%2B1%2B2n%2B1%3D2m%2B2n%2B2%3D2%28m%2Bn%2B1%29)
So,
∉ A
![xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1](https://tex.z-dn.net/?f=xy%3D%282m%2B1%29%282n%2B1%29%3D4mn%2B2m%2B2n%2B1%3D2%282mn%2Bm%2Bn%29%2B1)
So,
∈ A
Therefore, A is not closed under addition but A is closed under multiplication.
c.
![Let A=\{2,5,8,11,14,...\}](https://tex.z-dn.net/?f=Let%20A%3D%5C%7B2%2C5%2C8%2C11%2C14%2C...%5C%7D)
Let
but
∉A
Also,
∉A
Therefore, A is not closed under addition and multiplication.
d.
Let A = { 17n: n∈Z}
Let
∈ A such that ![x=17n,y=17m](https://tex.z-dn.net/?f=x%3D17n%2Cy%3D17m)
Find x + y and xy
![x+y=17n+17m=17(n+m)](https://tex.z-dn.net/?f=x%2By%3D17n%2B17m%3D17%28n%2Bm%29)
![xy=(17m)(17n)=289mn=17(17mn)](https://tex.z-dn.net/?f=xy%3D%2817m%29%2817n%29%3D289mn%3D17%2817mn%29)
So,
∈ A
Therefore, A is closed under addition and multiplication.
e.
Let A be the set of nonzero real numbers.
Let
∈ A such that ![x=-1,y=1](https://tex.z-dn.net/?f=x%3D-1%2Cy%3D1)
Find x + y
![x+y=-1+1=0](https://tex.z-dn.net/?f=x%2By%3D-1%2B1%3D0)
So,
∈ A
Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.
Therefore, A is not closed under addition but A is closed under multiplication.
Assuming you meant the x2 as x squared, then:
(11x+4)(11x-4)
Answer:
37.7cm
Step-by-step explanation:
The distance formula is given by:
![d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%20%7D)
We are given two points A and B as
A(1,1) and
B(7,-7)
so we have ,
x1 = 1 , y1=1
x2= 7 and y2=-7
Plugging these in the formula we have:
![d=\sqrt{(7-1)^{2}+(-7-1)^{2} }](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%287-1%29%5E%7B2%7D%2B%28-7-1%29%5E%7B2%7D%20%7D)
d=√(36+64)
d=√100
d=10
Answer: The distance between A(1,1) and B(7,-7) is 10