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alexandr1967 [171]
3 years ago
12

Gwen is sending a box to a friend. The box weights 23.5 pounds. Gwen removes a 4.47-pounds book to decrease the shipping cost. W

hat is the new weight of the box?
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0
23.5 - 4.47 = 19.03. Your final answer: “Gwen’s new box weighs 19.03 pounds”
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Please help me out with this question, THANKS!
sasho [114]

Answer:

line B.)

Step-by-step explanation:

2x+5y=10

5y=-2x+20

(5y/5) (2x+10/5)

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8 0
3 years ago
A parcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 84 in. What are
Lesechka [4]

Answer:

a) \frac{28}{\pi} in

b) 28 in

c) 784 in²

Step-by-step explanation:

Let the length be 'L'

and the radius be 'r'

Thus, according to the question

L + 2πr = 84 in

L = 84 - 2πr   ............(1)

Volume of the cylinder, V = πr²L

substituting the value of L from 1, we get

V =  πr²(84 - 2πr)

or

V = 84πr² - 2π²r³

for points of maxima, differentiating the above equation and equating it to zero

\frac{dV}{dr}=\frac{d(84\pi r^2-2\pi^2 r^3))}{dr}

or

2(84)πr - 3(2)π²r² = 0

or

2πr(84 - 3πr) = 0

or

r = 0    and    84 - 3πr = 0

or

⇒ 3πr = 84

or

⇒ r = \frac{28}{\pi} in

since, the radius cannot be zero therefore, r = 0 is neglected

Therefore,

a) The radius of the largest cylindrical package = \frac{28}{\pi} in

b) from  (2)

L = 84 - 2πr

or

⇒ L = 84 - 2\pi\times\frac{28}{\pi}

or

⇒ L = 84 - 56 = 28 in

The length of the largest cylindrical package = 28 in

c ) The volume of the largest cylindrical package ,V = πr²L

= \pi\times\frac{28}{\pi}\times28

= 784 in²

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3 years ago
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Answer:

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Step-by-step explanation:

you divide $44.00 by 8 which will give you $5.05 then you multiply $5.05 by 12.

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F(x) = x^2 + 4x-12
Ahat [919]

Answer:

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Step-by-step explanation:

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3. Armani has $7.00 in her purse consisting of nickels, dimes, and quarters. The total
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Answer:

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Step-by-step explanation:

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