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3 years ago

Which is a correct classification for the triangle?

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

8 0

I would believe it would be right triangle or a acute.
I would say it’s a right triangle is a higher chance

masya89 [10]3 years ago

4 0

B) right angle triangle
angles in a triangle add up to 180 degrees
31+59=90
180-90=90
90 degrees is a right angle

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Select all quantities that are proportional to the diagonal length of a square.

horsena [70]

Answer:

B. Perimeter of a square and

C. Side length of a square

Step-by-step explanation:

if n= side length of square then

Area of square is $n^{2}$
Perimeter of a square is 4×n
diagonal length of a square is $\sqrt{2}$ × n

Thus,

Perimeter of square can be expressed as

$2\sqrt{2}$ ×diagonal length of a square

Side length of a square can be expressed as

$\frac{1}{\sqrt{2} }$ ×diagonal length of a square

but Area of square is

$\frac{1}{\sqrt{2} }$ ×n×diagonal length of a square

As a Result, Area of square is <em>also dependent of the value n</em>, wheras in other cases it is <em>a proportion of diagonal length of a square</em>

5 0

3 years ago

Rewrite using the distributive property 6(x + 3)

alekssr [168]

Answer: 6x+18

Step-by-step explanation: Because of the Distributive property, you would multiply the 6 by the’x’ and 3, as they are in the parenthesis.

4 0

4 years ago

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Find the volume of the prism

AlekseyPX

Answer:

80 units³

Step-by-step explanation:

→ State the formula

Length × Width × Height

→ Substitute in the values

8 × 2 × 5

→ Simplify

80 units³

6 0

2 years ago

The types of Geometry that mathematicians study are:

Fiesta28 [93]

Option B i.e. Non-Euclidean

8 0

4 years ago

Which of the following statements must be true about the polynomial function f(x)? If 1+ the sqrt of 13 is a root of f(x), then

son4ous [18]

The correct answer is: if $1 + 13i$ is a root of $f(x)$ , then $1 - 13i$ is also a root of $f(x)$ .

In fact, every polynomial has real and/or complex solutions. If all solutions are real, we're good. But if not all of them are real, then the complex ones come in couple of conjugate solutions. Since $1 + 13i$ and $1 - 13i$ are conjugate complex numbers, if one of them is a solution, the other must be as well.

7 0

3 years ago

Read 2 more answers