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seraphim [82]
3 years ago
13

Please help ## look at the photo for question

Mathematics
2 answers:
Talja [164]3 years ago
4 0

Answer:

There is no photo, but just tell me what your doing and I can help!

Step-by-step explanation:

Andru [333]3 years ago
4 0
There's no picture bro-
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A washer and a dryer cost $928 combined. The washer costs $78 more than the dryer. What is the cost of the dryer?
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Step-by-step explanation:

$425

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Solve:<br>3 = -2v - V<br>V=​
Y_Kistochka [10]

Answer:

V = −1

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3=−2v−v

3=−2v+−v

3=(−2v+−v)(Combine Like Terms)

3=−3v

3=−3v

Step 2: Flip the equation.

−3v=3

Step 3: Divide both sides by -3.

<u>−3v</u>  = <u>3</u>

-3     -3

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4 years ago
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4 years ago
What is the period of the graph of the equation y = a sin bx?
steposvetlana [31]

T=2π/|b|. The period of an equation of the form y = a sin bx is T=2π/|b|.

In mathematics the curve that graphically represents the sine function and also that function itself is called sinusoid or sinusoid. It is a curve that describes a repetitive and smooth oscillation. It can be represented as y(x) = a sin (ωx+φ) where a is the amplitude, ω is the angular velocity with ω=2πf, (ωx+φ) is the oscillation phase, and φ the initial phase.

The period T of the sin function is T=1/f, from the equation ω=2πf we can clear f and substitute in T=1/f.

f=ω/2π

Substituting in T=1/f:

T=1/ω/2π -------> T = 2π/ω

For the example y = a sin bx, we have that a is the amplitude, b is ω and the initial phase φ = 0. So, we have that the period T of the function a sin bx is:

T=2π/|b|

7 0
3 years ago
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