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CaHeK987 [17]
3 years ago
12

Reduce to simplest form. -5/8+(-8/5)=?

Mathematics
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

-2\frac{9}{40}

Step-by-step explanation:

-\frac{5}{8}+(-\frac{8}{5}) = -\frac{25}{40}-\frac{64}{40} (find common denominator)

=-\frac{89}{40}

=-2\frac{9}{40} (reduce to simplest form)

Hope this helps :)

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A study is done by a community group in two neighboring colleges to determine which one graduates students with more math classe
stealth61 [152]

Answer:

t=\frac{(4-3.5)-0}{\sqrt{\frac{1.5^2}{11}+\frac{1^2}{9}}}}=0.890  

The p value for this case would be:

p_v =P(t_{18}>0.890)=0.193  

The p value is higher than the significance level so then we can conclude that we can FAIL to reject the null hypothesis and then the true mean for group A is not significantly higher than the mean for B

Step-by-step explanation:

Information given

\bar X_{1}=4 represent the mean for sample A

\bar X_{2}=3.5 represent the mean for sample B

s_{1}=1.5 represent the sample standard deviation for A

s_{2}=1 represent the sample standard deviation for B  

n_{1}=11 sample size for the group A

n_{2}=9 sample size for the group B  

\alpha=0.1 Significance level provided

t would represent the statistic

Hypothesis to test

We want to verify if the student who graduates from college A has taken more math classes, on the average, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2} \leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

The statistic is given by:

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=11+9-2=18  

Replacing we got:

t=\frac{(4-3.5)-0}{\sqrt{\frac{1.5^2}{11}+\frac{1^2}{9}}}}=0.890  

The p value for this case would be:

p_v =P(t_{18}>0.890)=0.193  

The p value is higher than the significance level so then we can conclude that we can FAIL to reject the null hypothesis and then the true mean for group A is not significantly higher than the mean for B

5 0
4 years ago
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