Our aim is to calculate the Radius so that to use the formula related to the area of a segment of a circle, that is: Aire of segment = Ф.R²/2
Let o be the center of the circle, AB the chord of 8 in subtending the arc f120°
Let OH be the altitude of triangle AOB. We know that a chord perpendicular to a radius bisects the chord in the middle. Hence AH = HB = 4 in
The triangle HOB is a semi equilateral triangle, so OH (facing 30°)=1/2 R. Now Pythagoras: OB² = OH² + 4²==> R² = (R/2)² + 16
R² = R²/4 +16. Solve for R ==> R =8/√3
OB² = OH² +
Answer:
3 6/8
Step-by-step explanation:
5 = 5
10/8 = 1 2/8
5 - 1 = 4
4 - 2/8 = 3 6/8
First you need to find the y-intercept, which is y = -1
Next is we need to find the slope of the line > you are going to have to do this by finding to clear point
The ones that I will be using are: (3, 1); (6, 3) (You could take any points)
Now using the slope formula we could find m.
m = y2-y1 / x2-x1
(1 - 3) / (3 - 6) = m
-2 / -3 = m
m = 2/3
Using the linear function format: y = mx + b
Therefore the equation of the line is y = 2x/3 -1
Answer:
7-3n
Step-by-step explanation:
3 less than 7.................. 7-3
times a number ............ n
Together ......................... 7-3n
D. X/36cm
DE= X. And AB= 36cm
