The ticket price of the item after applying coupon B first and then coupon A is $65.45
Coupons reduce the ticket price of an item.
<u><em>Ticket price</em></u><u><em> after </em></u><u><em>coupon B i</em></u><u><em>s applied </em></u>
An item costs $80. After applying the coupon B which gives, $3 off the price, the cost of the item reduces to $77 ($80 - $3).
The ticket price of the item after coupon B is applied is $77
<em><u>Ticket price </u></em><em><u>after c</u></em><em><u>oupon A </u></em><em><u>is applied </u></em>
The item costs $77 when coupon B is applied. If the discount is 15% off on coupon A, it means that the item costs 85%( 100 - 15%) of its initial price.
Ticket Price of the item = percentage price x price of the item after the first coupon B was applied
85% x $77
0.85 x $77 = $65.45
A similar question was solved here: brainly.com/question/17413216?referrer=searchResults
Answer:
64 numbers
Step-by-step explanation:
Answer:
Step-by-step explanation:
1st . 1.3^2= 1.69
1.4^2= 1.96
It's not bettween 1.3 & 1.4
2. 1.4^2=1.96
1.5^2= 2.25
it's betteen 1.4 & 1.5
3 . 1.4 & 1.5 so it's eqaul 1.4
Answer:
x+2
Step-by-step explanation:
x^3+6x^2+11x+6/x^2+4x+3
= x^3+6x^2+11x+6/x^2+4x+3
= (x+1)(x+2)(x+3)/(x+1)(x+3)
=x+2
Answer:
Step-by-step explanation:
Sin(30) / X = Sin(45) / 12
use algebra to isolate X
1 / X = [ Sin(45) / 12 ] / Sin(30)
flip both sides
X = Sin(30) / [Sin(45) /12 ]
invert the denominator on the right side
X = Sin(30) * 12/ Sin(45)
Do you know what Sin(30) is off the top of your head?
and also Sin(45) ?
these are worth remembering... and you can b/c they are just
sin(0) = 0/2
sin(30) = 1 / 2
sin(45) = 
/2
sin(60)= 
/ 2
sin(90) = 
/ 2 (aka 1)
note the numerators just counts up 0, 1, 2, 3, 4 :)
Cos works the same way but counts from 90° back to 0 but exactly like sin other wise, hence why Cos and Sin both = /2 at 45 °
anyway
X = 1 / 2 * 12/ /2
X = 3
A=3
B= 2
:) nice , huh
