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zubka84 [21]
3 years ago
7

The length of a rectangle is 10 in more than 5 times the width. The perimeter is

Mathematics
1 answer:
jarptica [38.1K]3 years ago
6 0

Answer:

50

Explanation

Area=L x w

Area = 10 x 5

50

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Find the vertex of the parabola y = 8x2.
murzikaleks [220]

Answer:

vertex is at (0,0)

Step-by-step explanation:

Find the vertex of the parabola y = 8x2.

I assume you meant   y =  8* x^2

this can be compared to the general vertex form  y = a (x - h)^2 + k

where vertex at  (h, k)

so then...

h =0  and k = 0 here

vertex is at (0,0)

7 0
3 years ago
0.8 is 20% of what number?
Rom4ik [11]

0.8 is 20% of 4. This is because 20% of something occurs when something is divided by 5, since it is 1/5 of 100. You multiply 0.8*5, and you get 4.

6 0
3 years ago
Sin(60-theta)sin(60+theta)​
ehidna [41]

Step-by-step explanation:

\sin(60 -  \theta)  \sin(60 +  \theta)  \\  =  \{ \sin(60)  \cos( \theta)  -  \sin( \theta)   \cos(60)  \} \{ \sin(60)  \cos( \theta)  +  \cos(60)  \sin( \theta)  \} \\  =  \{ \frac{ \sqrt{3} }{2}  \cos( \theta)  -  \frac{1}{2}  \sin( \theta)  \} \{ \frac{ \sqrt{3} }{2}  \cos( \theta)  +  \frac{1}{2}  \sin( \theta)  \} \\  \\

from difference of two squares:

{ \boxed{(a - b)(a + b) = ( {a}^{2} -  {b}^{2} ) }}

therefore:

=  \{ {( \frac{ \sqrt{3} }{2}) }^{2}  { \cos }^{2}  \theta \} -  \{ {( \frac{ \sqrt{3} }{2} )}^{2}  { \sin }^{2}  \theta \} \\  \\  =  \frac{3}{4}  { \cos }^{2}  \theta -  \frac{3}{4}  { \sin}^{2}  \theta

factorise out ¾ :

=  \frac{3}{4} ( { \cos }^{2}  \theta  -  { \sin}^{2}   \theta) \\  \\  = { \boxed{ \frac{3}{4}  \cos(2 \theta) }}

3 0
3 years ago
Read 2 more answers
What is 9-(-5) please help me​
elena-14-01-66 [18.8K]

9-(-5)=

9 + 5 (because - - = +)

14

thus 9-(-5) = 14

4 0
3 years ago
Please help ASAP!<br> Please PLEase
Amiraneli [1.4K]

Answer:I'm 80% sure it is c?!?!

Step-by-step explanation:

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