All categories

3 years ago

Will mark Brainiest!! Help asap

Mathematics

1 answer:

lys-0071 [83]3 years ago

7 0

Answer:

Step-by-step explanation: because thats my answer

You might be interested in

Someone please help.

vitfil [10]

Answer:

not correct

tan 60 = x / 2

square root(3) = x / 2

x = 2 * Square root(3)

= Square root ( 4 * 3) = Square root (12)

4 0

3 years ago

Convert 83% into a decimal<br> can you guy help me to do that

PilotLPTM [1.2K]

To convert a percentage to decimal form, you need to divide the number in the percent by 100. In reality, that just looks like moving the decimal point to the left two places.

83% / 100 = 0.83

83% in decimal form is 0.83.
Hope that helped! =)

6 0

3 years ago

Randy is painting part of a wall, excluding the two corners shown in white. a gallon of white paint will cover 100 sqaure feet.

uysha [10]

Randy needs to purchase 1.49 Gallons of paint to cover 100 sq. feet wall.

What is the area of rectangle?

The area of a rectangle is the product of its length and width. That is, A = l x w where l is the length and w is the width of the rectangle.

Here, Required Paint = $20 X \frac{37}{4} - 2 X \frac{1}{2}X6 X 6\\$

= 5 X 37 - 36

= 185 - 36

= 149

= 1.49 gallons

Thus, Randy needs to purchase 1.49 Gallons of paint to cover 100 sq. feet wall.

Learn more about Area of Rectangle from :

brainly.com/question/20693059

#SPJ1

4 0

2 years ago

Five and thirty-nine thousandths in standard decimal form

Nesterboy [21]

Answer:

Five and thirty-nine thousandths in standard decimal form is

5.039

Hope This Helps!!!

7 0

2 years ago

Suppose <img src="https://tex.z-dn.net/?f=m" id="TexFormula1" title="m" alt="m" align="absmiddle" class="latex-formula"> men and

ollegr [7]

Firstly, we'll fix the postions where the $n$ women will be. We have $n!$ forms to do that. So, we'll obtain a row like:

$\underbrace{\underline{~~~}}_{x_2}W_2 \underbrace{\underline{~~~}}_{x_3}W_3 \underbrace{\underline{~~~}}_{x_4}... \underbrace{\underline{~~~}}_{x_n}W_n \underbrace{\underline{~~~}}_{x_{n+1}}$

The n+1 spaces represented by the underline positions will receive the men of the row. Then,

$x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m~~~(i)$

Since there is no women sitting together, we must write that $x_2,x_3,...,x_{n-1},x_n\ge1$ . It guarantees that there is at least one man between two consecutive women. We'll do some substitutions:

$\begin{cases}x_2=x_2'+1\\x_3=x_3'+1\\...\\x_{n-1}=x_{n-1}'+1\\x_n=x_n'+1\end{cases}$

The equation (i) can be rewritten as:

$x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m\\\\
x_1+(x_2'+1)+(x_3'+1)+...+(x_{n-1}'+1)+x_n+x_{n+1}=m\\\\
x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-(n-1)\\\\
x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-n+1~~~(ii)$

We obtained a linear problem of non-negative integer solutions in (ii). The number of solutions to this type of problem are known: $\dfrac{[(n)+(m-n+1)]!}{(n)!(m-n+1)!}=\dfrac{(m+1)!}{n!(m-n+1)!}$

[I can write the proof if you want]

Now, we just have to calculate the number of forms to permute the men that are dispposed in the row: $m!$

Multiplying all results:

$n!\times\dfrac{(m+1)!}{n!(m-n+1)!}\times m!\\\\
\boxed{\boxed{\dfrac{m!(m+1)!}{(m-n+1)!}}}$

4 0

3 years ago