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Misha Larkins [42]
3 years ago
8

Write in terms of i Simplify your answer as much as possible. square root of -48

Mathematics
1 answer:
grandymaker [24]3 years ago
7 0
The square root of -48 is 2 because 2x2x2x2x2x2x is not -48
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A car leaves its garage and travels for 30km on a bearing of 145, then 10 km on a bearing of 250 Calculate a) the distance trave
OverLord2011 [107]

The distance travelled from the starting point is 29 km , the bearing is 344 degree

The missing diagram is attached with the answer.

<h3>What is Bearing Angle ?</h3>

It is the horizontal angle between the object and another object.

It is given that the car starts from point travels for 30km on a bearing of 145, then 10 km on a bearing of 250

(a) the distance travelled from the starting point

It can be understood from the diagram that

To determine the distance , b is to determined4

By applying Cosine rule

b² = a² +c²-2ac cos\rm \theta

b² = 10²  +30²  - 2* 30*10 cos75

b² = 100+900 -600* 0.2588

b² = 100-155.2914

b² = 844.7

b = 29 km

Therefore the distance travelled from the starting point is 29 km.

(b) the bearing of the starting point from the car.

To determine the bearing ,

angle C has to be determined

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sin C / c = sin B / b

sin C = sin 75 * 30 / 29

sin C = 0.9970

C = sin⁻¹ 0.9970

C = 85.59 degree

angle C = α +70 degree

α  = 15.59 degree

Bearing = 70 + 20 + 9 0 + 90+74 = 244 degree

To know more about Bearing

brainly.com/question/9214012

#SPJ1

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1 year ago
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