Penjelasan langkah demi langkah:
1)
![= 243^{\frac{2}{3} }\\= (\sqrt[3]{243})^2\\= 7^2\\= 49](https://tex.z-dn.net/?f=%3D%20243%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D%5C%5C%3D%20%28%5Csqrt%5B3%5D%7B243%7D%29%5E2%5C%5C%3D%207%5E2%5C%5C%3D%2049)
2) √32 +3√18-2√50
= √16*2 +3√9*2-2√25*2
= 4√2 + 3(3√2)-2(5√2)
= 4√2 + 9√2-10√2
= 13√2-10√2
= 3√2
3) 1000 ⅔×64⅙
![= (\sqrt[3]{1000}) ^2 \times (2^6)^{1/6} \\= 10^2 \times 2\\= 100 \times 2\\= 200](https://tex.z-dn.net/?f=%3D%20%28%5Csqrt%5B3%5D%7B1000%7D%29%20%5E2%20%5Ctimes%20%282%5E6%29%5E%7B1%2F6%7D%20%20%5C%5C%3D%2010%5E2%20%5Ctimes%202%5C%5C%3D%20100%20%5Ctimes%202%5C%5C%3D%20200)
4) 3/4+√2
5) 2√3×√18
= 2√3×√9*2
= 2√3×3√2
= (2*3)(√3*√2)
= 6√6
6) 12/3+√3
= 4+√3
7) √1000—2√40
= 10 -2 (√4*10)
= 10-2(2√10)
= 10 - 4√10
8) 2- ¹+3-¹
9)
Jika pernyataannya opsional, penyebutnya adalah 1
10) 2√3×√18
= 2√3×√9*2
= 2√3×3√2
= (2*3)(√3*√2)
= 6√6
The equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
Given a quadratic function for the transformations given the function f(x) = x²
If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value
- Translating the graph 1 unit up will give the final function g(x) as (x-4)² + 1 (We added 1 since it is an upward translation.)
Hence the equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
Learn more here: brainly.com/question/15381183
Answer:
(Kind of cheating but since you're timed I'm just gonna five you the answer:
3/11
Step-by-step explanation:
I got this by guessing a bit, I used what varibles I had and 0.27 & 3 and used them.
So 3/0.27 = 11.11 (Repeating) so then I rounded this to a whole number,
3/11 = 0.27 (Repeating)
Z - 7 = 8
subtract 7 from both sides
z = 15
hope this helped!
