The percent composition of Uranium in U308 = C. 81.03%
<h3>Further explanation</h3>
Given
X g of U
3.795 g of O
20.00 g of U308
Required
The percent composition of Uranium
Solution
mass of Uranium in U308 :
= mass of U308 - mass of O
= 20 g - 3.795 g
= 16.205 g
The percent composition :

%U = (mass U/mass U308) x 100%
%U= (16.205/20) x 100%
%U = 81.025≈81.03
Answer:
The H in the carboxyl group.
Explanation:
Acetic acid can be written as CH₃COOH, where -COOH is the functional group carboxyl, responsible for the acidity of organic acids. The H in the carboxyl group is the one that is donated in the acid reaction.
CH₃COOH(aq) + H₂O(l) ⇄ CH₃COO⁻(aq) + H₃O⁺
Acetic acid is a weak acid, so just a small fraction of the molecules undergo this reaction to donate their hydrogen.
A molecule is a neutrally charged group of atoms held together by one or more COVALENT bonds