Answer:
Explanation:Reaction NaHCO3 + HCl ⇒ NaCl + H2O + CO2
Molar mass M = (22.99+1.008+ 12.01+3·16 ) g/mol. Calculate
Amount of substance n =m/M, n(NaCl) is equal.
M(NaCl) = 58.44 g/mol and mass m= n·M
Answer:
3 is the correct answer i think
Explanation:
The answer is D: studying how the mayfly population affects the number of trout in a stream <span> As the science of ecology studies interactions between individual organisms and their environments.</span>
Answer:
The Answer is A
Explanation:
Please let me know if I am wrong
The amount of energy in kilocalories released from 49 g of glucose given the data is -4.4 Kcal
How to determine the mole of glucose
Mass of glucose = 49 g
Molar mass of glucose = 180.2 g/mol
Mole of glucose = ?
Mole = mass / molar mass
Mole of glucose = 49 / 180.2
Mole of glucose = 0.272 mole
How to determine the energy released
C₆H₁₂O₆ →2C₂H₆O + 2CO₂ ΔH = -16 kcal/mol
From the balanced equation above,
1 mole of glucose released -16 kcal of energy
Therefore,
0.272 mole of glucose will release = 0.272 × -16 = -4.4 Kcal
Thus, -4.4 Kcal were released from the reaction
Learn more about stoichiometry:
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