The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
f(2.1) = 48(2.1)-16(2.1)^2 = 30.25
etc.
f(2.05) = 31.16
f(2.01) = 31.8384
Now plug these values into the formula
(20-32)/0.5 = -24
(30.25-32)/0.1 = -17.5
etc.
= -16.8
= -16.16
Final answer:
2.5s => -24 ft/s
2.1s => -17.5 ft/s
2.05 => -16.8 ft/s
2.01 => -16.16 ft/s
Hope I helped :)
That would be the second choice. Translation of 2 to the left
(y+2) (x+5) this your answer
Answer:
18 Kilometers
Step-by-step explanation:
If you divide 12 by 4 you get 3, so she is going about 3 kilometers an hour. Add 3 for each hour, and you get 18 kilometers in 6 hours.
Since we’re trying to find minutes, concert all known information to minutes
1 hr 15 mins = 75 mins
1 hr 30 mins = 90 mins
Next, calculate how many total minutes Gage has skated in the first 8 days
75(5) + 90(3) = 645 mins
Create an equation to find the average of Gage’s minutes of skating. Add up all the minutes and divide by the total amount of days and set equal to 85, the average we are trying to get.
(645 mins + x mins)/9 days = 85
Solve for x
645 + x = 765
x = 120
So, in order to have an average of an 85 minute skate time, Gage would need to skate 120 minutes on the ninth day.
