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MakcuM [25]
3 years ago
11

Round 0.090999 to four decimal places.

Mathematics
1 answer:
baherus [9]3 years ago
5 0

0.0910, I think.

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My dyslexia did not like theese numbers

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7. Which pair shows equivalent expressions? A. 3(x+2) = 3x + 6 B. 3x + 2x = x²(x + 2) C. 3x + 2 = 3(x + 2) D. -3(2 + x) = -6x -
Sergio039 [100]
C has equivalent expressions I think
8 0
3 years ago
Solve 765/14 and write your answer in terms of a mixed number (please use this format: 75 3/5). *
kozerog [31]

the answer is 54 9/14

because Divide using long division. The whole number portion will be the number of times the denominator of the original fraction divides evenly into the numerator of the original fraction, and the fraction portion of the mixed number will be the remainder of the original fraction division over the denominator of the original fraction.

6 0
3 years ago
Read 2 more answers
Select the correct answer.
Maru [420]

Answer:

B

Step-by-step explanation:

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6 0
3 years ago
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The triangles are similar. If QR = 9, QP = 6, and TU = 19, find TS. Round to the nearest tenth.
Feliz [49]
QR=9
QP=6
TU=19
TS=?
Okay so the triangles are kindred, now the equation can be made
9/16=6/x
So now we are going to cross multiply
9x=114
Now divide both sides by
912 2/3
Your answer is:
TS=12.6
4 0
3 years ago
A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to
melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}

Mean of X:

E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42

Variance of X:

E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}

var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58

5 0
4 years ago
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