Which equation can be used to find the side lengths if the longest side measures 6.2cm?

PLEASE HELP WILL MARK BRAINLIEST!

pantera1 [17]

Answer:

Make a coordinate plane and you have to solve around the origin say 4,4 and 4,1.

Step-by-step explanation:

8 0

3 years ago

Hellppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

const2013 [10]

Answer: y = 4 and x = 1

Step-by-step explanation:

when y is 2, x is 0.5

when y is 4, x is 1

.(+ 2) .(+ 0.5)

the rule is that y is 4 times larger than x

5 0

2 years ago

Read 2 more answers

✓

ikadub [295]

Answer:

the corresponding sides and angles would be a pair of matching angles or sides that are in the same spot in two different shapes.

Step-by-step explanation:

So look at triangle AWXV and check each side....does side AW correspond with other triangle AX - meaning they are the same?

Repeat to find the same angle in each triangle that matches.

8 0

3 years ago

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

8 0

3 years ago

You have 8 songs, 10 podcasts, and 12 audio books on your iCloud. How many ways can you choose 1 of each to download to your iPh

Fofino [41]

Answer:

960 ways

Step-by-step explanation:

Multiplication Principle: if there are n ways to do one thing and m ways to do another, then there are m x n ways to do both.

That can expand to include three things (or more).

8 x 10 x 12 = 960

4 0

2 years ago