What is the minimum point of the equation x^2+19=9x

Mathematics

1 answer:

azamat3 years ago

3 0

Answer:

The minimum point is (4.5, -1.25).

Step-by-step explanation:

x^2+19=9x

= x^2 - 9x + 19 = 0

Convert to Vertex form:

(x - 4.5)^2 - 4.5^2 + 19 = 0

= (x - 4.5)^2 - 1.25.

The minimum point is (4.5, -1.25).

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the axis of symmetry of a quadratic equation is x = –3. if one of the zeroes of the equation is 4, what is the other zero?

FinnZ [79.3K]

ANSWER

The other zero is

$x = - 10$

EXPLANATION

The axis of symmetry serves as the midpoint of the two zeroes.

We were given that the axis of symmetry of the quadratic equation is
$x = - 3$

We were also given that, one of the zeroes of the quadratic equation is
$x = 4$

Let the other zero of the quadratic equation be
$x = p$

,then, we apply the midpoint formula to find the value of
$p$

Since it is the x-values of the intercepts that gives the solution, we use only the x-value part of the midpoint formula which is given by,

$\frac{x_1 + x_2}{2} = axis \: of \: symmetry$

We substitute to obtain,

$\frac{p + 4}{2} = - 3$

We multiply through by 2 to get,

$p + 4 = - 6$

This implies that,

$p = - 6 - 4$

$p = - 10$

3 0

3 years ago

Read 2 more answers

Please help me idk this

GarryVolchara [31]

Answer:

Step-by-step explanation:

$A=\dfrac{bh}{2}\\\\A=117\ cm^2\\b=13\ cm$