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Anettt [7]
3 years ago
12

Marking brainliest! If you were to build a rollercoaster, what would you name it and why?

Mathematics
1 answer:
Murljashka [212]3 years ago
7 0

Answer:

mango because you go around the roller coater thats shaped as a mango and it smells like mangos

Step-by-step explanation:

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Pls help i dont understand :( will give Brainliest + 25 Points
umka21 [38]
It’s D. 4 is the one next to X because that’s what is changing and -3 is the y intercept which comes after X
3 0
4 years ago
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In a one-tail test, the p-value is found to be equal to .068. If the test had been two-tail, the p-value would have been
devlian [24]

Answer:

The p-value for two-tailed test is 0.136

Step-by-step explanation:

Given;

one-tail test, p-value = 0.068,

In one-tailed test, we test for the possibility of a relationship in one direction and completely disregard the possibility of a relationship in the other direction.

One-tail test provides possibility of an outcome in one direction, while

two-tail test provides possibility of an outcome in two different directions.

Thus, the p-value for two-tailed test = 2 x 0.068 = 0.136

3 0
3 years ago
6. Craig and James both live 4 miles up a hill. Craig hikes uphill at a rate of 1 mile every two hours.
Iteru [2.4K]

Answer:

James

Step-by-step explanation:

James rate:

2x + 2 = 4

2x = 2

x = 1 hour

Rate = distance/time = 4/1 = 4 miles per hour

Craig's rate = 1/2 = 0.5 miles per hour

James is faster

6 0
3 years ago
According to a medical study, 15% of people will experience an adverse side effect
ahrayia [7]

Answer:

c

Step-by-step explanation: trust me

6 0
3 years ago
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A box with a square base and an open top is being constructed out of A cm2 of material. If the volume of the box is to be maximi
viktelen [127]

Answer:

Side length = \sqrt{\frac{A}{3} } cm ,   Height =  \frac{1}{2} \sqrt{\frac{A}{3} } cm  ,  Volume = \frac{A\sqrt{A}}{6\sqrt{3} }  cm³

Step-by-step explanation:

Assume

Side length of base = x

Height of box = y

total material required to construct box = A ( given in question)

So it can be written as

A = x² + 4xy

4xy = A - x²

  1. y = \frac{A - x^{2} }{4x}

Volume of box = Area x height

V = x² ₓ y

V = x² ₓ ( \frac{A - x^{2} }{4x} )

V =  \frac{Ax - x^{3} }{4}

To find max volume put V' = 0

So taking derivative equation becomes

\frac{A - 3 x^{2} }{4} = 0

A = 3 x^{2}

x^{2} = \frac{A}{3}

x = \sqrt{\frac{A}{3\\} }

put value of x in equation 1

y = \frac{A - \frac{A}{3} }{4\sqrt{\frac{A}{3} } }  

y = \frac{2 \sqrt{\frac{A}{3} } }{4 \sqrt{\frac{A}{3} } }

y = \frac{1}{2} \sqrt{\frac{A}{3} }

So the volume will be

V = x^{2} × y

Put values of x and y from equation 2 & 3

V = \frac{A}{3} (\frac{1}{2} \sqrt{\frac{A}{3} } )

V = \frac{A\sqrt{A}}{6\sqrt{3} }

8 0
4 years ago
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