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Lubov Fominskaja [6]
3 years ago
11

6. Craig and James both live 4 miles up a hill. Craig hikes uphill at a rate of 1 mile every two hours.

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0

Answer:

James

Step-by-step explanation:

James rate:

2x + 2 = 4

2x = 2

x = 1 hour

Rate = distance/time = 4/1 = 4 miles per hour

Craig's rate = 1/2 = 0.5 miles per hour

James is faster

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Find m when 4^(m)*4^(2)=12
miv72 [106K]

Step-by-step explanation:

4^m * 4^2 = 12

4^(m + 2) = 4^(log4 12)

m + 2 = log4 (12)

m = log4 (12) - 2.

4 0
3 years ago
Find the area of the other polygon area=__ft
Colt1911 [192]

Answer:

108ft^2

Step-by-step explanation:

since you going up in value, you mulitple 3*9 to get 27. that means you have to multiple the other value of the bigger rectangle by 2. therefore 6*18=108

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Question 3<br> the figure needs solving help
AnnyKZ [126]

Answer:

ABC = 60

Step-by-step explanation:

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8 0
3 years ago
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gtnhenbr [62]

Answer:

1) B) 10

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8 0
3 years ago
Use each model to predict the life expectancy of residents of a country for which the average annual income is $80,000
Mandarinka [93]

The life expectancies of residents of a country for which the average annual income is $80,000 for the three models are 12309.9352, 172.2436 and 4828.1393

The life expectancies of the models are given as:

y =69.9352 + 0.1530\times (income) --- model 1

y =4.2436 + 0.0021\times (income) --- model 2

y =4.1393 + 0.0603\times (income) --- model 3

Given that the average annual income is $80,000;

We simply substitute 80000 for income in the equations of the three models.

So, we have:

<u>Model 1</u>

y =69.9352 + 0.1530\times (income)

y =69.9352 + 0.1530\times 80000

y =12309.9352

<u>Model 2</u>

y =4.2436 + 0.0021\times (income)

y =4.2436 + 0.0021\times 80000

y =172.2436

<u>Model 3</u>

y =4.1393 + 0.0603\times (income)

y =4.1393 + 0.0603\times 80000

y =4828.1393

Hence, the life expectancies are 12309.9352, 172.2436 and 4828.1393

Read more about linear models at:

brainly.com/question/8609070

4 0
3 years ago
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