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Lubov Fominskaja [6]
3 years ago
11

6. Craig and James both live 4 miles up a hill. Craig hikes uphill at a rate of 1 mile every two hours.

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0

Answer:

James

Step-by-step explanation:

James rate:

2x + 2 = 4

2x = 2

x = 1 hour

Rate = distance/time = 4/1 = 4 miles per hour

Craig's rate = 1/2 = 0.5 miles per hour

James is faster

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The difference between an open circle and a closed circle on a graph of an inequality.
Ilia_Sergeevich [38]

A closed circle means that value is included, and an open circle means that value is excluded.

Example:

x > 2 ---- Graphed with an open circle, everything greater than but not including 2

x ≤ 3 ------ Graphed with a closed circle, everything less than and including 3

3 0
3 years ago
Please help, photo attached.
steposvetlana [31]

The zeroes of the polynomial functions are as follows:

  • For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
  • For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
  • For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1

<h3>What are the zeroes of a polynomial?</h3>

The zeroes of a polynomial are the vales of the variable which makes the value of the polynomial to be zero.

The polynomials are given as follows:

f(x) = 2x(x - 3)(2 - x)

f(x) = 2(x - 3)²(x + 3)(x + 1)

f(x) = x³(x + 2)(x - 1)

For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2

For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1

For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1

In conclusion, the zeroes of a polynomial will make the value of the polynomial function to be zero.

Learn more about polynomials at: brainly.com/question/2833285

#SPJ1

5 0
1 year ago
Let r = ⟨7, 1⟩, s = ⟨–6, 2⟩, and t = ⟨–9, –3⟩. What is 10r + s – t? ⟨55, 9⟩ ⟨55, 15⟩ ⟨73, 6⟩ ⟨73, 15⟩
sergiy2304 [10]

Answer: d. 73,15

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
What is the true solution to the equation below? In e^in x + in e^in x^2 = 2 in 8
mariarad [96]
To solve the given equation, w need to review some rules:
(1) \ ln \ e = 1 \\ &#10;(2) \ ln \  b^{a} = a*ln \ b \\&#10;(3) \ ln \ a + ln \ b = ln \ (ab) \\&#10;(4) \ ln \ a - ln \ b = ln \  \frac{a}{b}  \\

The given equation is :
ln \  e^{ln \ x} + ln \  e^{ln \  x^{2}} = 2 \ ln \ 8
ln \ x * ln \ e + ln \  x^{2} * ln \ e = 2 \ ln \ 8  ⇒⇒⇒⇒ rule (2)
ln \ x + ln \  x^{2} = ln \  8^{2}  ⇒⇒⇒⇒ rule (1) and rule (2)

ln \ ( x*  x^{2} ) = ln \ 64          ⇒⇒⇒⇒ rule (3)
removing the nature logarithm from both sides

x^{3} = 64 =  4^{3}
∴ x = 4


So, the correct answer is option (2) ⇒⇒⇒⇒ x = 4


5 0
3 years ago
Read 2 more answers
Line m is parallel to Line n.
soldi70 [24.7K]
I hope this helps. Have a good day.

6 0
2 years ago
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